x2 + 6x + 5 = (x + 1)(x + 5)
(x + 1)(x + 5)
32
Suppose the number is x. Then x + 5/x = 6 Multiplying throughout by x, x2+5 = 6x or x2 - 6x + 5 = 0 which can be factorised into (x-1)*(x-5)=0 So x = 1 (and 5 times its reciprocal is 5) or x = 5 (and 5 times its reciprocal is 1).
x2 + 8x + 15 = (x + 3)(x + 5)
x2 + 6x + 5 can be factored into (x+1) (x+5)
Potential respondents would be assisted by knowing the sign of the 6x element as there is no solution in integers.
x2-12x+35 = (x-5)(x-7)
x2 + 6x + 5 = (x + 1)(x + 5)
6x5(x2 - 6x + 3)
(x - 5)(x - 8)
k = 5
(x - 3)(x - 2)
x2 - 6x + 5 = (x - 1)(x - 5)
(x + 1)(x + 5)
x2 + 6x - 5 is a quadratic expression that can not be factored.
(2x - 5) is a binomial factor