x² + 8x + 15 = (x + 5)(x + 3)
X2 + 8x + 16 = 10x +16x2 + 8x + 16=2x + 8x + 16=10x + 16
y = x2 + 8x + 15 = (x + 3)(x + 5). When y = 0, one or other of the two factors must equal zero; that is, x = -3 or -5, when y = 0.
x2 + 8x - 20 = (x - 2)(x + 10).
-8x+24 {This answer may be wrong: I think the question was intended to read, "Factor x2 - 10x + 24?" If so, the factors are (x - 6) and (x - 4)}
x2 + 8x + 15 = (x + 3) (x + 5).
x2-8x+15 = (x-3)(x-5)
That does not factor neatly.
x2 + 8x = x(x+8)
x + 4
x2 + 8x = -15 x2 + 8x + 15 = 0 since 15 = 5 x 3 and 5 + 3 = 8, then (x + 5)(x + 3) = 0 x + 5 = 0 or x + 3 = 0 x = -5 or x = -3
x² + 8x + 15 = (x + 5)(x + 3)
x2 + 8x + 12 = (x + 6) (x + 2)
(-4,-1)
(x + 6)(x + 2)
x2 - 8x + 32 = 0 (assuming)you can factor or use the quadratic equation.I recommend the quadratic equation.
No because the discriminant is less than zero.