One cent, (aka one penny), equals one hundreth of a dollar ($0.01).
There are 10 nickels, 20 dimes and 40 quarters in the cash register. The 10 nickels is 10 x 5 cents or 50 cents. The 20 dimes is 20 x 10 cents or 200 cents. The 40 quarters is 40 x 25 cents or 1000 cents. Converting and adding these, we get $0.50 + $2.00 + $10.00 = $12.50, which is the sum given in the question. Let's work through it. The number of nickels is N, the number of dimes is D and the number of quarters is Q. These are our variables in this problem. We don't know how many of them there are, and their numbers could vary. That's why we call them variables. We might also call them unknowns, too. A nickel is 5 cents, so the value of the nickels is the number of nickels, which is N, times the value of the nickel, which is 5 cents. That's 5N here. A dime is 10 cents, so the value of the dimes is the number of dimes, which is D, times the value of the dime, which is 10 cents. That's 10D here. A quarter is 25 cents, so the value of the quarters is the number of quarters, which is Q, times the value of the quarter, which is 25 cents. That's 25Q here. The sum of the values of the coins was given as $12.50, or 1250 cents, because we are working with coins, whose values are measured in cents. Further, we can write this expression as 5N + 10D + 25Q = 1250 on our way to the answer. Of the last two facts, the first was that there were twice as many dimes as nickels. We could write that as D = 2N because said another way, there are twice the number of dimes as nickels. We might also say that for every nickel, there are 2 dimes, so doubling the number of nickels will give us the number of dimes. The last fact is that there were twice as many quarters as dimes. We could write that as Q = 2D because said another way, thre are twice the number of quarters as dimes. We might also say that for every dime, there are 2 quarters, so doubling the number of dimes will give us the number of quarters. The last two bits of data we have allow us to solve the problem, because the do something special for us. Each bit of data expresses one variable in terms of another. That means we can make substitutions in our expressions for the sum of the values of the coins. Let's put up or original expression, and then do some substitutions. 5N + 10D + 25Q = 1250 This is the original expression. We know that D = 2N, so lets put the 2N in where we see D and expand things a bit. 5N + 10(2N) + 25Q = 1250 5N + 20N + 25Q = 1250 We changed the "look" of the expression, but we didn't change its value. Let's go on. We know that Q = 2D, so lets put that in. 5N + 20N + 25Q = 1250 5N + 20N + 25(2D) = 1250 5N + 20N + 50D = 1250 We're almost there. Remember that D = 2N, and we can substitute that in here. 5N + 20N + 50D = 1250 5N + 20N + 50(2N) = 1250 5N + 20N + 100N = 1250 Groovy! We have substituted variables and now have an expression with only one variable in it! Let's proceed. 5N + 20N + 100N = 1250 125N = 1250 We're close! N = 1250/125 = 10 N = 10 The number of nickels is 10, and because the nickel is 5 cents, the value of these coins is their number times their value, or 10 x 5 cents = 50 cents = $0.50 We were told the number of dimes was twice the number of nickels. This means that since there are 10 nickels, there will 2 x 10 or 20 dimes. And 20 x 10 cents = 200 cents = $2.00 We were also told the number of quarters was twice the number of dimes. This means that since there are 20 dimes, there will be 2 x 20 or 40 quarters. And 40 x 25 cents = 1,000 cents = $10.00 If we add the values of the coins, we should get the $12.50 that we were told was in the register. $0.50 + $2.00 + $10.00 = $12.50 We're in business. The value of each denomination of coins adds up to the given value of all the coins in the register. Piece of cake.
The question refers to the "following". In such circumstances would it be too much to expect that you make sure that there is something that is following?
360 degrees
A quarter is already 25¢-too much-so we have to try smaller ones. 5 pennies = 5¢. 1 dime = 15¢. 10 pennies = 10¢. 5 + 15 + 10 = 25¢, and 5 + 1 + 10 = 16 coins. Note: If this question is from work you have been assigned by a teacher or professor, I suggest you do the work yourself instead of trying to find the answers online. This will help you to better understand the material and become more familiar with it. Of course, if this question was not from homework, you can ignore this message.
Too simple: 1 quarter 2 dimes 2 nickels 4 pennies
Now - I'm British but... 4 quarters, 2 dimes and 4 cents are the minimum number of coins you would need to make $1.24 - a total of 10 coins.More:Because the question asks for the minimum number of coins, you want to use the largest number of the largest possible denomination to make up the total amount without exceeding the total. That is,Start with 4 quarters ($1) because 5 would be $1.25 which is too large.That leaves 24 cents, so the next denomination to try is a dime. Three dimes would be too much (30 cents) so you need to use two dimes.The quarters and dimes total $1.20 so only 4 cents remain. A nickel (5 cents) is too large, so you need four pennies to make up the full amount.
3 quarters, 1 dime, 1 nickel, and 5 pennies.
The correct way to write this alphabetically would be seventy four dollars and ninety cents.Some example sentences are:I have seventy four dollars and ninety cents in my purse.Seventy four dollars and ninety cents is a bit too much for a bowl of ice cream.The shopping came to a total of seventy four dollars and ninety cents.
There are two possible solutions: You could have one quarter, two dimes, two nickels and forty-five pennies, or you could have two dimes, eight nickels and forty pennies. An easy way of approaching this problem is to start by imagining that you have fifty pennies. You have the right number of coins, but are fifty cents short. Instead of adding other coins, you replace pennies with them: replacing a penny with a nickel gains four cents, a dime gains nine, and a quarter gains twenty-four. You can't possibly use more than two quarters, so there are few cases to consider there: If you replace two pennies with quarters, you've gained forty-eight cents, so you only need two more; but any further replacement will give you too much. If you use one quarter, you need to make up twenty-six more cents in steps of four or nine; it's easy to see that two of each works. Finally, with no quarters, you need to gain fifty cents using increments of four or nine; this yields the second solution.
A few coins called a 'dismes' were designed by Benjamin Franklin in 1778, but they weren't released to the public. Some additional experimental pieces were made in 1792 but they too weren't put into circulation. The first regular-issue US coins to be used by the general public were cents and half-cents released in 1793.
The mint struck half-cents and cents in pure copper. All other coins were either gold or silver alloyed with a small amount of copper for hardness. Nickel was not yet a practical coinage metal because it was too hard for the presses and dies of the time.
1943 cents were made of steel. Lead is far too soft for use in coins, as well as being poisonous if swallowed.
It is not possible to make 25 cents from 14 coins (US currency) There are only 1, 5, 10 and 25 cent coins Test: 14 x 1c = 14c, insufficient value 13 x 1c (=13) + 1 x 5c (=5) totals 18c, still not enough 12 x 1c (=12) + 2 x 5c (=10) totals 22c, still not enough. 11 x 1c (=11) + 3 x 5c (=15) totals 26c. Too much! If you use a 10c coin, you have to make the balance of 15c with 13 coins! Not possible! Of course, if you have 14 coins, which includes 10 x 1c (=10), and 3 x 5c (=15), you will easily make a total of exactly 25c, but only if you don't include the 14th coin!
Hawaii is part of the U.S. The "one dollar bill" is worth 100 cents, just as it is in all other U.S. states.
1964 Lincoln cents are very common, way too many original rolls and Mint bags still exist for the coin to have high values. Typical uncirculated coins sell for 5 to 10 cents.
You can not get banned on Club Penguin if you donate too many coins, but if you have a lower amount of coins (such as 4999 coins or lower), if you click on donate 5000 coins to any cause, without 5000 coins, you can still get the stamp.