All numbers that are divisible by 5 and 9 are multiples of their lcm which is 45.
So the question boils down to which multiples of 45 are between 1000 & 2000.
1000 ÷ 45 = 222/9
2000 ÷ 45 = 444/9
Thus the solution is the multiples of 45 from 23 to 44 which are:
1035, 1080, 1125, 1170, 1215, 1260, 1305, 1350, 1395, 1440, 1485, 1530, 1575, 1620, 1665, 1710, 1755, 1800, 1845, 1890, 1935, 1980
111 numbers between 5 and 1000 are divisible by 9
There are 232 numbers between 1 and 500 that are divisible by 3 or 5.
There are 5 numbers between 17 and 61 that are divisible by 8. They are 24, 32, 40, 48, and 56.
There are 267 such numbers.
10 numbers
111 numbers between 5 and 1000 are divisible by 9
There are 232 numbers between 1 and 500 that are divisible by 3 or 5.
There are 98 numbers are between 1 and 100 that are divisible by five.
-- All of the numbers that end with a zero are divisible by 10.-- All of those, and all of the numbers that end with a 5, are also divisible by 5.
-- All of the numbers that end with a zero are divisible by 10.-- All of those, and all of the numbers that end with a 5, are also divisible by 5.
set of odd numbers divisible by 2 between 10 and 20
There are 466 numbers between 1 and 1,000 that are divisible by three or five.
There are 599 numbers between 1 and 1,000 that are divisible by two or five.
5, 10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95,100
All numbers that end in 0 or 5.
There are 5 numbers between 17 and 61 that are divisible by 8. They are 24, 32, 40, 48, and 56.
There are 267 such numbers.