All numbers that are divisible by 5 and 9 are multiples of their lcm which is 45.
So the question boils down to which multiples of 45 are between 1000 & 2000.
1000 ÷ 45 = 222/9
2000 ÷ 45 = 444/9
Thus the solution is the multiples of 45 from 23 to 44 which are:
1035, 1080, 1125, 1170, 1215, 1260, 1305, 1350, 1395, 1440, 1485, 1530, 1575, 1620, 1665, 1710, 1755, 1800, 1845, 1890, 1935, 1980
111 numbers between 5 and 1000 are divisible by 9
There are 232 numbers between 1 and 500 that are divisible by 3 or 5.
There are 5 numbers between 17 and 61 that are divisible by 8. They are 24, 32, 40, 48, and 56.
10 numbers
There are 267 such numbers.
111 numbers between 5 and 1000 are divisible by 9
There are 232 numbers between 1 and 500 that are divisible by 3 or 5.
There are 98 numbers are between 1 and 100 that are divisible by five.
-- All of the numbers that end with a zero are divisible by 10.-- All of those, and all of the numbers that end with a 5, are also divisible by 5.
-- All of the numbers that end with a zero are divisible by 10.-- All of those, and all of the numbers that end with a 5, are also divisible by 5.
set of odd numbers divisible by 2 between 10 and 20
There are 466 numbers between 1 and 1,000 that are divisible by three or five.
There are 599 numbers between 1 and 1,000 that are divisible by two or five.
5, 10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95,100
All numbers that end in 0 or 5.
There are 5 numbers between 17 and 61 that are divisible by 8. They are 24, 32, 40, 48, and 56.
Nine of them are evenly divisible by 5, if you include 20 and 60.