The hundredths.
Well, honey, the 5 in the ten-thousands place is 50,000 and the 5 in the tens place is just 50. So, technically, the 5 in the ten-thousands place is 49,950 greater than the 5 in the tens place. Math can be a real hoot sometimes!
10: 1190 100: 1200 1000: 1000
A 1000 is 100 times greater than 10 and so 100*10 = 1000
1000
Ten out of every 100 numbers from 150 to 959 . . . . . 90 times.
4
It is 1000 times greater because 1000 times 0.09 = 90
If you mean as in 90.09 then it is 1000 times greater because 1000*0.09 = 90
995 to the nearest tens is 1000. When rounding to the nearest tens, you look at the digit in the ones place. If it is 5 or greater, you round up; if it is less than 5, you round down. In this case, the digit in the tens place is 9, which is 5 or greater, so you round up to the nearest tens, which is 1000.
Well, honey, the 5 in the ten-thousands place is 50,000 and the 5 in the tens place is just 50. So, technically, the 5 in the ten-thousands place is 49,950 greater than the 5 in the tens place. Math can be a real hoot sometimes!
To find how many times the digit 2 occurs in the tens place from 100 to 1000, we can analyze the range of numbers. The relevant range for the tens place is from 120 to 229, which includes all numbers where the tens digit is 2. This gives us the numbers 120-129 (10 occurrences), 220-229 (10 occurrences), totaling 20 occurrences of the digit 2 in the tens place.
this is what i got in my stupid math book from school this is the dumbest ? ever
To find how many times the digit '9' appears between 1 and 1000, we can count the occurrences in each digit place (hundreds, tens, and units). In the range from 1 to 999, '9' appears 300 times: 100 times in the units place (from 9, 19, ..., 999), 100 times in the tens place (from 90 to 99, 190 to 199, ..., 990 to 999), and 100 times in the hundreds place (only 900 to 999). Including 1000, which does not contain a '9', the total remains 300.
To find how many times the digit '1' appears between 1 and 1000, we can analyze each digit place (hundreds, tens, and units) separately. In the range from 1 to 999, '1' appears 300 times: 100 times in the hundreds place (100-199), 100 times in the tens place (10-19, 110-119, ..., 910-919), and 100 times in the units place (1, 11, 21, ..., 991). Adding '1' for the number 1000 gives a total of 301 occurrences of the digit '1'.
10: 1190 100: 1200 1000: 1000
No solution.If it's greater than 3400, then its hundreds place must be '4'.Then (4) times (its tens place) = 2. There is no integer that can go in the tens place and make this true.
1000