In mathematics, XN typically represents a variable (X) raised to a power (N). This is known as exponentiation, where X is the base and N is the exponent. The expression XN is equal to multiplying X by itself N times. For example, X2 means X squared, which is X multiplied by itself two times.
(xn+2-1)/(x2-1)ExplanationLet Y=1+x2+x4+...+xn. Now notice that:Y=1+x2+x4+...+xn=x2(1+x2+x4+...+xn-2)+1Y+xn+2=x2(1+x2+x4+...+xn-2+xn)+1Y+xn+2=x2*Y+1Y+xn+2-x2*Y=1Y-x2*Y=1-xn+2Y(1-x2)=1-xn+2Y=(1-xn+2)/(1-x2)=(xn+2-1)/(x2-1)
The sequence is xn = xn-1 + 2
25.2
xn--
What you need to do is look for a common term throughout the expression. i.e. something that is multiplying everypart of the expression. In this case the common term is n. This common term goes on the outside the bracket: n(x-y) = xn - yn
This is represented as the algebraic expression xn/n or xn ÷ n.
In mathematics, XN typically represents a variable (X) raised to a power (N). This is known as exponentiation, where X is the base and N is the exponent. The expression XN is equal to multiplying X by itself N times. For example, X2 means X squared, which is X multiplied by itself two times.
If by "xn" you mean ax^n then the answer is "a"
xn = xn-1 - (n + 2).
A polynomial is a sum of a finite number of terms in which each term is of the form a*Xn where a is a coefficient, X is a variable and n is a non-negative integer.a may be integer, rations, real or complex;X may be a numerical variable or a matrix.
xn=x1+(n-1)v<t xn=10+6(n-1) xn=4+6n
Principle of Duality helps us to find the possible correct boolean expression. "Any theorem or identity in switching algebra remains true if 0 and 1 are swapped and . and + are swapped." Mathematically f(x1,x2,...,xn,.,+,1,0)=f(x1,x2,...,xn,+,.,0,1) Important point to note is that dual of expression different from the complement of expression. Mathematically f(x1,x2,...,xn,.,+,1,0)=f(x1`,x2`,...,xn`,+,.,0,1); i.e. if x1 belongs to positive logic then x1` denotes the negative logic and vice versa. De-morgans law is helps us to obtain the complement of expression.
(xn+2-1)/(x2-1)ExplanationLet Y=1+x2+x4+...+xn. Now notice that:Y=1+x2+x4+...+xn=x2(1+x2+x4+...+xn-2)+1Y+xn+2=x2(1+x2+x4+...+xn-2+xn)+1Y+xn+2=x2*Y+1Y+xn+2-x2*Y=1Y-x2*Y=1-xn+2Y(1-x2)=1-xn+2Y=(1-xn+2)/(1-x2)=(xn+2-1)/(x2-1)
xn+1 = 1/2 ( xn + N/xn )
xn- yn=(x - y)(xn-1 + xn-2y +xn-3y2 +. . .+x2yn-3+xyn-2 + yn-1)
Y=Xn Y/n=X