What you need to do is look for a common term throughout the expression.
i.e. something that is multiplying everypart of the expression.
In this case the common term is n. This common term goes on the outside the bracket:
n(x-y) = xn - yn
exponent exponent
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factor I (fibrinogen), factor II (prothrombin), factor III (tissue thromboplastin), factor IV (calcium), factor V (proaccelerin), factor VI (no longer considered active in hemostasis), factor VII (factor-vii), factor VIII (antihemophilicfactor), factor IX (plasma thromboplastincomponent; Christmas factor), factor X (stuart-factor-stuart-prower-factor), factor XI (plasma thromboplastinantecedent), factor XII (factor-xii), factor XIII (fibrin stabilizing factor).
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factor pair = 36,1 factor pair = 18,2 factor pair = 12,3 factor pair = 9,4 factor pair = 6,6
xn- yn=(x - y)(xn-1 + xn-2y +xn-3y2 +. . .+x2yn-3+xyn-2 + yn-1)
The answer is 28.
What is the only perfect number of the form Xn + Yn
What is the question ? This is the equation of a line in 3 dimensions. Every point on the line satisfies the equation. There's no question here that needs an answer.
Andrew Wiles solved/proved Fermats Last Theorem. The theorem states Xn + Yn = Zn , where n represents 3, 4, 5,......... there is no solution.
Theorem: If two similar triangles have a scalar factor a : b, then the ratio of their perimeters is a : bBy the theorem, the ratio of the perimeters of the similar triangles is 2 : 3.For rectangles, perimeter is 2*(L1 + W1). If the second rectangle's sides are scaled by a factor S, then its perimeter is 2*(S*L1 + S*W1) = S*2*(L1 + W1), or the perimeter of the first, multiplied by the same factor S.In general, if an N-sided polygon has sides {x1, x2, x3....,xN}, then its perimeter is x1 + x2 + x3 + ... + xN. If the second similar polygon (with each side (labeled y, with corresponding subscripts) scaled by S, so that y1 = S*x1, etc. The perimeter is y1 + y2 + ... + yN = S*x1 + S*x2 + ... + S*xN = S*(x1 + x2 + ... + xN ),which is the factor S, times the perimeter of the first polygon.
exponent exponent
(xn+2-1)/(x2-1)ExplanationLet Y=1+x2+x4+...+xn. Now notice that:Y=1+x2+x4+...+xn=x2(1+x2+x4+...+xn-2)+1Y+xn+2=x2(1+x2+x4+...+xn-2+xn)+1Y+xn+2=x2*Y+1Y+xn+2-x2*Y=1Y-x2*Y=1-xn+2Y(1-x2)=1-xn+2Y=(1-xn+2)/(1-x2)=(xn+2-1)/(x2-1)
xn+1 = 1/2 ( xn + N/xn )
If the relationship can be written as y = ax + b where a and b are constants then it is a linear transformation. More formally, If f(xn) = yn and yi - yj = a*(xi - xj) for any pair of numbers i and j, then the transformation is linear.
the answer would be exponentthe n in x indicating the number of factor of x is exponent
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