If we look at each letter individually and determine if they are a vowel or a consonant, the word anonymous is technically has 5 consonants, n, n, y, m, and s. However, sometimes the letter y is used as a vowel. The word anonymous is one of these cases.
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You have written 6 of them in your question - what, words, consonants, next, each, other I hope this helps
for vowels=8/13; for consonants=5/13; sample space |S|=13
one
In the word DAUGHTER, there are 3 vowels namely, A, U, and E, and 5 consonants namely, D, G, H, T, and R. Number of ways of selecting 2 vowels out of 3 vowels = Number of ways of selecting 3 consonants out of 5 consonants = Therefore, number of combinations of 2 vowels and 3 consonants = 3 × 10 = 30 Each of these 30 combinations of 2 vowels and 3 consonants can be arranged among themselves in 5! ways. Hence, required number of different words = 30 × 5! = 3600