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The modulus of a number relative to a base is the positive remainder when itis divided by that base. So

-24 mod 7 = (-28 + 4) mod 7 = -28 mod 7 + 4 mod 7 = 4 mod 7 = 4while

24 mod 7 = (21 + 3) mod 7 = 21 mod 7 + 3 mod 7 = 3 mod 7 = 3.

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What two integers multiplied equal -24?

Pairs of integers which when multiplied equal -24 are: -3 8 -4 6 -6 4 -12 2 -24 1 3 -8 4 -6 6 -4 12 -2 24 -1


Are four eighths and two sixths equal?

No. Convert to equivalent fractions with the same denominator and compare numerators: 4/8 = (4×3)/(8×3) = 12/24 2/6 = (2×4)/(6×4) = 8/24 12 does not equal 8, so 12/24 does not equal 8/24, thus 4/8 does not equal 2/6.


What is one-third times 4 times 3 times 6 equal?

24. 4x3x6 = 72 1/3 of 72 is 24.


How can you make 7 5 9 8 equal 24 using each number only once?

9-5=4 7-4=3 3*8=24


What is the remainder when the product of 100 5's are divided by 7?

The remainder is 2. Knowing how to do modular arithmetic makes the problem much easier to solve. We say a number x has a value of k "mod" 7 if dividing x by 7 leaves a remainder of k. Multiples of 7 are equal to 0 mod 7 (they leave no remainder), and 32 is equal to 4 mod 7, because 32 / 7 = 4 remainder 4. The product of 100 5s is equal to 5 to the 100th power, or 5^100 in shorthand. Let us look at what the first few powers of 5 are equal to mod 7: 5^1 = 5 = 5 mod 7 5^2 = 25 = 4 mod 7 5^3 = 125 = 6 mod 7 5^4 = 625 = 2 mod 7 5^5 = 3125 = 3 mod 7 5^6 = 15625 = 1 mod 7 5^7 = 78125 = 5 mod 7 5^8 = 390625 = 4 mod 7 It looks as if we might have a repeating pattern, and indeed the next few powers of 5 are equal to 6, 2, and 3, confirming that 5^k = 5^(k-6) mod 7. This means that 5^100 has the same remainder after dividing by 7 as 5^94, which has the same remainder as 5^88, etc. etc. until we reach 5^4, which leaves a remainder of 2. Therefore by induction 5^100 leaves a remainder of 2. Hope this all makes sense.