Well a parallelogram is a 4 sided shape with 2 pairs of parallel lines, hence PARALLELogram.
That's the reason, because there are two pairs of parallel lines.
A=l*w A=8*4 A=32 diagonal cuts the rectangle into two congruent triangles. 32/2 = 16
Three triangles
yes
Yes - divide the hexagon by drawing a line connecting two opposite sides, dividing it in half. (Drawing a line connecting two angles will only result in two congruent quadrilaterals).
4/(7) = 4/7 is the ratio of circles to triangles. Some prefer to express this as 4:7.
No, in general, it does not.
The answer is: usually not.
Yes It always does because of how a trapezoid is shaped.
A=l*w A=8*4 A=32 diagonal cuts the rectangle into two congruent triangles. 32/2 = 16
It is helpful (not help full) because the two triangles formed by either diagonal are congruent.
When you draw a diagonal in a rectangle or a parallelogram, it divides the shape into two congruent triangles, meaning both triangles are the same size and shape. In contrast, drawing a diagonal in a trapezoid results in two triangles that can differ in size and shape, as the bases of the trapezoid are unequal. Thus, different size and shape triangles form only in the trapezoid.
No, it is not possible to divide a trapezium into two congruent triangles. A trapezium has only one pair of parallel sides, while a triangle has no parallel sides. Therefore, it is not geometrically feasible to divide a trapezium into two congruent triangles.
Yes. Read on for why: Take a parallelogram ABCD with midpoints E and F in the bases. So something like this (forgive the "drawing"): A E B __.__ /__.__/ C F D We know that parallelogram AEFC = EBDF, since they have the same base (F bisects CD, so CF = FD), height (haven't touched that), and angles (<ACF = <EFD because they're parallel - trust me that everything else matches). We also know that every parallelogram can be divided into two congruent triangles along their diagonal. So if two congruent parallelograms consistent of two congruent triangles each, then all four triangles are congruent. So your congruent triangles are ACF, AEF, EFD, and EBD. You can further reinforce this through ASA triangle congruency proofs (as I did at first), but this is a far more concise and equally valid answer.
A heptagon has seven sides, so when drawing diagonals from one vertex, it will create five triangles. This is because each diagonal drawn from a single vertex will create a triangle until it intersects the previous diagonal. Therefore, the number of triangles formed by drawing all diagonals from one vertex in a heptagon is five.
To find interior angle measurements, you must divide the shape into triangles by drawing diagonal lines. The diagonal lines draw triangles, and the interior angle measure of triangles are always 180 degrees. The sum of interior angles of an octagon is 1080 degrees. How ever many triangles you have, multiply it by 180. See octagons in the link for more help,
This result follows from the theorem that the sum of the angles of a triangle is 180 degrees. Drawing a diagonal in the quadrilateral splits it into two triangles and the angles of the triangles together combine to form the angles of the quadrilateral.
A polygon that can be divided into 4 triangles is a quadrilateral. A quadrilateral is a polygon with four sides and four vertices. By drawing a diagonal from one vertex to the opposite vertex, a quadrilateral can be divided into two triangles. By drawing another diagonal from the other two vertices, the quadrilateral can be further divided into a total of four triangles.