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Electrophilic substitution occurs in furan, thiophene, and pyrrole because these compounds have a lone pair of electrons on the heteroatom (oxygen, sulfur, or nitrogen), making them nucleophilic and reactive towards electrophiles. The aromaticity of these compounds is also maintained during the substitution reaction, making them favorable candidates for electrophilic substitution.
Furan does not typically undergo nucleophilic substitution reactions because of its aromatic nature, which offers stability due to delocalization of the pi electrons in the ring. This makes furan less reactive towards nucleophilic attack compared to non-aromatic compounds.
pyridine is less reactive than benzene because when we form its conjugate base then it'll b more stable than dat of benzene.. so more stabler means less reactive.......and also due to more resonance in benzene it will b more reactive...same 4 furan and pyrrole
When furan reacts with maleic anhydride, it forms a Diels-Alder adduct called endo-3,6-epoxy-1,2,3,6-tetrahydrophthalic anhydride. This reaction is a type of cycloaddition reaction that involves the formation of a new ring structure.
It is made on industrial scale by treating pentose with heat and a strong acid (like sulfuric acid). This leads to formation of furane-2-carbaldehyde. The aldehyde can be removed by reaction with zinc oxide @ 400 degrees C, giving unsubstituted furan.
Furan is more reactive than Pyrrole because it is less stable as it contains an extra lone pair than that of pyrrole, which is available for attack of an acid, results in the destabilization of the ring.
Furan is prone to oxidation reactions in the presence of air. This oxidation process causes the molecular structure of furan to change, leading to the formation of brown-colored compounds as byproducts. This is why furan turns brown when exposed to air.
Furan is insoluble in ether because furan is a polar compound and ether is a nonpolar solvent. Like dissolves like, so the polarity mismatch between furan and ether prevents them from forming a homogeneous solution.
Pyrrol has a lone pair of electrons on the nitrogen atom, which is more available for donation compared to the lone pair on oxygen in furan. This makes pyrrole more basic than furan.
no. the answer why is listed in the text book macroscale and microscale organic experiments by williamson. I remember reading the reason there i just dont remember why. Yes, the answer why the reaction didn't work is in the reading of the text. I just finished this lab this week. The question is IF the reaction had worked, would cantharidin been formed. To answer this, I would draw out the mechanism of this reaction (remember this is all hypothetical) and remember that the exo/endo orientation is important in determining this answer!
Yes, furan is a polar compound due to the presence of polar covalent bonds in the molecule. The oxygen atom in furan is more electronegative than carbon, leading to an uneven distribution of electron density and creating a polar molecule.
furan though has a lone pair of electron which is not delocalised but due to high electronegetivity of oxygen it is not a available for donation hence has weak basic proerty