bag
ok here we go...Proof:If the some graph G has the same DFS and BFS then that means that G should not have any cycle(work out for any G with a cycle u will never get the same BFS and DFS .... and for a graph without any cycle u will get the same BFS/DFS).We will prove it by contradiction:So say if T is the tree obtained by BFS/DFS, and let us assume that G has atleast one edge more than T. So one more edge to T(T is a tree) would result in a cycle in G, but according to the above established principle no graph which has a cycle would result the same DFS and BFS, so out assumption is a contradiction.Hence G should have more edges than T, which implies that if the BFS and DFS for a graph G are the same then the G = T.Hope this helps u......................
1. bfs uses queue implementation ie.FIFO dfs uses stack implementation ie. LIFO 2. dfs is faster than bfs 3. dfs requires less memory than bfs 4. dfs are used to perform recursive procedures.
DFS and BFS are both searching algorithms. DFS, or depth first search, is a simple to implement algorithm, especially when written recursively. BFS, or breadth first search, is only slightly more complicated. Both search methods can be used to obtain a spanning tree of the graph, though if I recall correctly, BFS can also be used in a weighted graph to generate a minimum cost spanning tree.
dfs better then from bfs..
The population of BFS Group Ltd is 4,200.
Hillclimbing proceeds as per values of each nodes.Whereas BFS follows edges of the tree.
No. why
going to the gym,daily.
Banking & Financial Sector
No you don't.
BFS: This can be throught of as being like Dijkstra's algorithm for shortest paths, but with every edge having the same length. However it is a lot simpler and doesn't need any data structures. We just keep a tree (the breadth first search tree), a list of nodes to be added to the tree, and markings (Boolean variables) on the vertices to tell whether they are in the tree or list. Depth first search is another way of traversing graphs, which is closely related to preorder traversal of a tree. Recall that preorder traversal simply visits each node before its children. It is most easy to program as a recursive routine: