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Why is186 426 is divisible by both 3 and 9?
It is because 186426 = 3*62142 and 186426 = 9*20714.
Is 117 divisible by 9?
Yes. 117/9=13. An easy test for divisibility by nine (for an integer of any length) is to add all of the digits. If the sum is nine or a number divisible by nine, then the integer is divisible by nine. In this case, 1+1+7=9, so 117 is divisible by nine. (Be careful, this test fo divisibility only works generally for divisibility by three -- i.e., an integer is divisible by three if and only if the sum of its digits equals three or a multiiple of three-- and for nine.) To find if an integer is divisible by 4, you can check if the last two digits are. If they are, it is. To check if an integer is divisible by 6, you must make sure that the integer is divisible by both 3 and 2. If you want to check if an integer is divisible by 2, just make sure it's even. Any integer divisible by 10 will end in zero. Any integer divisible by 5 will end in either 5 or 0. This is an important part of pre-algebra, as well as algebra.
Why is 531 divisible by 3 and 9?
Because three and nine go into 531 evenly.
Is 9 divisible by 75?
No, 75 is not evenly divisible by nine.
Is 159 divisible by 9?
No. 159 is not evenly divisible by nine.
