No. 426 is only divisible by: 1, 2, 3, 6, 71, 142, 213, 426.
No. But it is divisible by: 1 2 3 6 71 142 213 and 426.
Any number that is divisible by both 2 and 3 is divisible by 6.
The number that is between 40 and 50 and is divisible by both 3 and 5 is 45. To determine if a number is divisible by both 3 and 5, you must ensure it is divisible by both 3 and 5 without leaving a remainder. In this case, 45 meets this criteria as it is divisible by both 3 (45 รท 3 = 15) and 5 (45 รท 5 = 9).
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
Yes as both divisible by 3 so 15/426 = 5/142
No. 426 is only divisible by: 1, 2, 3, 6, 71, 142, 213, 426.
No. But it is divisible by: 1 2 3 6 71 142 213 and 426.
Yes.
No, it is clearly a multiple of 2, making it not a prime number.
No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
They are both divisible by 1 and 3
1, 2, 3, 6, 9, 18, 71, 142, 213, 426, 639, 1278
Any number that is divisible by both 2 and 3 is divisible by 6.
426-3 = 423
2 yes, 3 no.
9 is divisible by both 3 and 9