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The third quadrant.

Q: Which quadrant would an answer be in if tan was positive and sin was negative?

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csc θ = 1/sin θ → sin θ = -1/4 cos² θ + sin² θ = 1 → cos θ = ± √(1 - sin² θ) = ± √(1 - ¼²) = ± √(1- 1/16) = ± √(15/16) = ± (√15)/4 In Quadrant III both cos and sin are negative → cos θ= -(√15)/4

No, they cannot all be negative and retain the same value for theta, as is shown with the four quadrants and their trigonemtric properties. For example, in the first quadrant (0

0.75

Yes: cosecant = 1/sine If sine negative, 1/sine is negative → cosecant is negative.

d/dx(-cosx)=--sinx=sinx

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The tangent function is equal to the sine divided by the cosine. In quadrant III, both sin and cos are negative - and a negative divided by another negative is positive. Thus it follows that the tangent is positive in QIII.

The value of tan and sin is positive so you must search quadrant that tan and sin value is positive. The only quadrant fill that qualification is Quadrant 1.

There's a mnemonic for this: All Students Take Calculus. Starting in the first quadrant, and moving counterclockwise until the last, give each quadrant the first letter of thos words in order. A represents all 3, s represents sine, t represents tangent, and c represents cosine. If the letter appears in a quadrant, it is positive there. If not, it is negative there.In quadrant 2, only sine is positive.

sin pi/2 =1 sin 3 pi/2 is negative 1 ( it is in 3rd quadrant where sin is negative

negative

Since theta is in the second quadrant, sin(theta) is positive. sin2(theta) = 1 - cos2(theta) = 0.803 So sin(theta) = +sqrt(0.803) = 0.896.

Consider angles in standard position, and note that for the equation sin Î¸ = 0.5, the angle in the first quadrant is Î¸ = 30Â° The sin function is positive in quadrants I and II, and negative in quadrants III and IV, so there are two basic answers, one in quadrant III and another in quadrant IV. In quadrant III, the angle is 180Â° + 30Â° = 210Â° In quadrant IV, the angle is 360Â° - 30Â° = 330Â° Of course, this is a wave function so there are an infinite number of answers. You can add full circles (i.e. multiples of 360Â°) to either of these answers to get more answers. In quadrant III, the angles are 210Â°, 570Â°, 930Â°, ... In quadrant IV, the angles are 330Â°, 690Â°, 1050Â°, ...

It is not! So the question is irrelevant.

That follows from the definition of the sine function. There are several equivalent definitions, but for example, it can be defined as the y-coordinate of the unit circle, as a function of the angle. You start measuring the circle from coordinates (1,0), and continue counterclockwise. _________________________________________ This is because both sin definition is the length of line opposite to the angle divided by the angle side line. Since both lines are positive in the first quadrant, the sin value is positive.

tan = sin/cos Now cos2 = 1 - sin2 so cos = +/- sqrt(1 - sin2) In the second quadrant, cos is negative, so cos = - sqrt(1 - sin2) So that tan = sin/[-sqrt(1 - sin2)] or -sin/sqrt(1 - sin2)

Assuming sin equals 0.3237, the angle is in quadrant I.

There is no such angle, since the sine of an angle cannot be greater than 1.