-- Their sum is (36 + 34) = 70, not 72.
-- Their difference is (36 - 34) = 2, not 4.
-- Other than that, 36 and 34 are a terrific answer ! But 38 and 34 would be better.
They are: 33+34 = 67
They are (33, 34, 35).
The numbers are 32, 33, 34 and 35.
11 and 6
Adding all integers from 33 to 112 inclusive gives you 5800.
The integers are -34 and -33.
They are: 16+18 = 34
-34 and -33
They are: 33+34 = 67
They are (33, 34, 35).
33, 34, 35, 36
The numbers are 32, 33, 34 and 35.
3 and 5
The integers are -37, -36 and -35. Also, using consecutive even integers: -38, -36 and -34.
32+33+34=99
The two even consecutive integers that have a sum of 70 are 34 and 36. This is because if we let the first integer be ( x ), then the next consecutive even integer is ( x + 2 ). Setting up the equation ( x + (x + 2) = 70 ) simplifies to ( 2x + 2 = 70 ), leading to ( 2x = 68 ) and ( x = 34 ). Thus, the integers are 34 and 36.
It's an imaginary number, one that exists only in fiction, if the author wants it to. There are no two consecutive integers whose sum is 66. 32 + 33 = 65 33 + 34 = 67 The sum of two consecutive integers is always an odd number.