You simply count the number of eights that are being multiplied together, and that is your exponent. In this case that would be: 8⁵
because, ,lets say i have the number.. 6 so six groups of one (below) 1 1 1 1 1 1 or one group of six . 6. so count the ones in the first one. 1 1 1 1 1 1 it equals six. and count one group of six.. 6. I hope I helped
1. Start 2. Read Number (the number of which you want the table) 3. Count=1 4. Print N*Count ( multiplying the number,from step 2, with count) 5. Is count=10? If yes, then STOP. If no then Add one to the Count.
Count the number of digits after the decimal point in the first number being multiplied. Count the number of digits after the decimal point in the second number being multiplied. Add the two numbers. This is the number of digits after the decimal point in the answer. But make sure that any trailing 0s are included. To calulate 0.42 * 3.451: 41*3451 = 144942 Digits after point in first number = 2 Digits after point in second number = 3 2 + 3 = 5 So digits after point in answer = 5 So answer = 1.44942 But To calulate 0.42 * 3.45: 42*345 = 14490 <<< it is vital that the last 0 here is kept till the last stage. Digits after point in first number = 2 Digits after point in second number = 2 2 + 2 = 4 So digits after point in answer = 4 So answer = 1.4490 = 1.449
1 is the highest number you can count to using a mod-2 counter.
Least Count [L.C]:-Least count is minimuim acuurate value meauserd by instrument.Least Count of Vernier Callipers:-The minimum value measured is 0.1mm but nowa days [l.c] is of 0.5mm.'
0.1mm It is the range of verniercalliper. As it has least count 0.1mm that's why its range is 0.1 mm in physics laboratory
The least count of a vernier scale is calculated by dividing the smallest division on the main scale by the total number of divisions on the vernier scale. This calculation gives the value of one vernier division.
The least count of a vernier scale in a diffraction grating is typically determined by the formula for the number of lines per unit length on the grating. By dividing the distance between two adjacent lines on the scale by this number, you can calculate the least count of the vernier scale.
The least value which can be measured from any measuring instrument or device is called its least count. Generally the least count of a vernier caliper is 0.02mm.You can get a least count of 0.01mm in Digital vernier caliper.
The least count of the vernier can be measured by using the formula stated below. Least count (L.C) = 1 M.S.D - 1 V.S.D Example; vernier scale is constructed by taking 49 main scale divisions dividing them into 50 divisions ie. 49mm divided into 50 parts therfore 1 vsd=49/50 mm=0.98mm 1 MSD=1mm substituting in formula L.C = 1 M.S.D - 1 V.S.D L.C=1-0.98=0.02mm
Least count of an instrument means the minimum measurement which can be measured by that instrument correctly. For example various vernier callipers has the least count of 0.01cm. This means that if we measure the length of object below 0.01cm then it will not be correct and can have error. This also means that its reading is correct upto 2 decimal place.
The least count of a vernier scale is the smallest measurement that can be read or determined on the main scale. It is calculated by dividing the smallest division on the main scale by the total number of divisions on the vernier scale. A smaller least count allows for more precise measurements to be taken.
The least count of the vernier caliper is calculated by dividing the smallest division on the main scale by the total number of divisions on the vernier scale. In this case, 1 cm on the main scale is divided into 20 equal parts, so the least count is 1 cm / 20 = 0.05 cm or 0.5 mm.
.02mm
1)Main Scale is fixed(It does not move) Vernier scale slides along main scale.2)Least count of Mainscale is 0.1cmLeast count of vernier scale is 0.01cm
LC= Value of one main scale division Total number of divisions on vernier