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128 = 8*8*2

so sqrt(128) = sqrt(8*8*2) = sqrt(8*8)*sqrt(2)

= sqrt(82)*sqrt(2)

= 8*sqrt(2) since the sqrt of a square is the number itself.

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Q: Why is the square root of 128 8 root 2?
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What is the square root of 128 in radical form?

Oh, dude, the square root of 128 in radical form is 8√2. It's like 8 times the square root of 2, you know? So, if you're into math or just trying to impress your friends with your radical knowledge, there you go.


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