128 = 8*8*2
so sqrt(128) = sqrt(8*8*2) = sqrt(8*8)*sqrt(2)
= sqrt(82)*sqrt(2)
= 8*sqrt(2) since the sqrt of a square is the number itself.
The square root of 128 is 8 times the square root of 2 because it's an irrational number. An estimate is 11.313708498984760390413509793678
the square root of 128 or 8 times the square root of 2.
Oh, dude, the square root of 128 in radical form is 8√2. It's like 8 times the square root of 2, you know? So, if you're into math or just trying to impress your friends with your radical knowledge, there you go.
The number that, when raised to the power of 2, equals 128 is the square root of 128. The square root of 128 is approximately 11.31. Therefore, 11.31 raised to the power of 2 equals 128.
8√2i
The square root of 128 is 8 times the square root of 2 because it's an irrational number. An estimate is 11.313708498984760390413509793678
the square root of 128 or 8 times the square root of 2.
Oh, dude, the square root of 128 in radical form is 8√2. It's like 8 times the square root of 2, you know? So, if you're into math or just trying to impress your friends with your radical knowledge, there you go.
The square root of negative 128 can be expressed using imaginary numbers. First, we can rewrite it as (\sqrt{-128} = \sqrt{128} \cdot \sqrt{-1}). The square root of 128 simplifies to (8\sqrt{2}), so we have (\sqrt{-128} = 8\sqrt{2}i), where (i) is the imaginary unit. Thus, the simplified form is (8\sqrt{2}i).
The square root of 128 can be simplified in surd form as follows: ( \sqrt{128} = \sqrt{64 \times 2} = \sqrt{64} \times \sqrt{2} = 8\sqrt{2} ). Thus, the square root of 128 in surd form is ( 8\sqrt{2} ).
The number that, when raised to the power of 2, equals 128 is the square root of 128. The square root of 128 is approximately 11.31. Therefore, 11.31 raised to the power of 2 equals 128.
8√2i
8 times [ square root of 2 ] .
8 x y1.5 sqrt(2)
The square root of 128 is not an irrational number; it can be simplified. Specifically, (\sqrt{128} = \sqrt{64 \times 2} = \sqrt{64} \times \sqrt{2} = 8\sqrt{2}). Since (\sqrt{2}) is irrational, (\sqrt{128}) is also irrational.
-1281/2 = -11/2 * 1281/2 = i * 1281/2 = i * 641/2 * 21/2 = i * 8 * 21/2Short of now calculating the value and writing this as a multiple of i this is as simplified as it can be.The square root of -128 = 8i * 21/2(note: x1/2 means "the square root of x").
square root 2 times square root 3 times square root 8