That's not a binary number ! Binary numbers can only use the digits 1 and 0.
'2' Decimal code => '10' Binary code.
All possible 2-bit numbers ... 0, 1, 2, and 3 ... are the same in BCD and binary. No conversion is required.
Binary ( 1 0 ) = decimal ( 2 )
In a simple way, write down the numbers from right to left: 1,2,4,8,16,32,64 and 128. Binary one is 000001. (write this above or below the other numbers I just gave you) The number two is 000010 in binary. Three is 000011. Four is 000100. Five is 000101. You should see the pattern. The Binary number corresponds to the placement of ones and zeros to 128 64 32 16 8 4 2 1.
11001 16 + 8 + 1
First let's write it as a sum of powers of two. This will make it easier to write as a binary number. 19=16+2+1 This can be written: 19=16*1+8*0+4*0+2*1+1*1 So the binary form is: 10011
The number 200 written as a binary number is 11001000
The number 1 as a binary number is 1
Decimal 28 is 11100 in binary
212 (decimal) is 11010100 (binary)
This is my own way of finding a binary of a number. We all know that binary is in base 2 (it only have 2 values - 0 and 1). Here is how I do it:Steps:1) Divide the number by 2. If there is a remainder, then write the number 1 as the first binary number otherwise write 0.Ex:7/2 = 3.5 ---> Since there's a remainder write 1.8/2 = 4 ---> If there's no remainder write 0.2) Repeat the first step using the value that was derived on the first one. Continue doing so until the number is not less than 1Ex:3/2 = 1.5 ---> Our binary now is 11.4/2 = 2 ---> Our binary here is 00.Repeat:1/2 = 0.5 ---> Since the number is less than zero, just write the final result. Our binary now is 111.2/2 = 1 ---> Again here we write 000.1/2 = 0.5 ---> Now we write it as 0001.3) After getting the final value, reverse your answer and it will now be the binary form.Answer:710 = 1112810 = 10002Note: Please edit my answer if you are a bit confuse with the steps.
10
10110
The base units; 8 4 2 1 9 in binary: 1 0 0 1 So 1001...because 9 = 8 + 1
710 = 1112
You write the number as a sum of decreasing powers of 2. Then for each power, you write 1 if it is present in the sum and 0 if not.So, 3 = 2 + 1 = 2^1 + 2^0and so the binary for 3 (in decimal) is 11.