X2 plus y2 plus 4y plus 16x equals 1 in standard form?

Answer 1

Complete the square [a^2 +b + (-b/2a)^2]= (original answer)+ (-b/2a)^2 so (x^2+16x+64)+(y^2+4y+4)=1+64+16 then factor/simplify (x+8)^2 + (y+2)^2 = 101 this woudl be a circle with a center of (-8,-2) and a radius of (101)^(1/2), or the square root of 101