b = y - mx.
y-b/x=m
There is no difference; it is a matter of choice and convention as to what letter is used.
y = mx + b
Y = 2X + 1 Now it is.
b = y - mx.
y-b/x=m
you multiply m n p
Y = mX + 6 Y - 6 = mX (Y - 6)/X = m ==============If you had values you could get the integer that is m
If y = mx + b, then x = (y-b)/m (for m not equal to zero).
the answer is: (y-b)/x = m y = mx + b y - b = mx (y-b)/x = m
yes
It depends on what you are trying to solve for. Here is a solution for x... y = mx + b y - b = mx (y - b) / m = x Note: If m is zero, then there is no solution, because the line is horizontal
What do you mean by "solve"? Do you want to rearrange it, solving for x? That would be: x = (y - b) / m Do you want to find it's derivative with respect to x? Then the answer is: y' = m Do you want to find it's indefinite integral? That'd be: ∫y dx = mx2/2 + bx + C
7x + y = 8 Subtract 7x from each side of the equation: y = -7x + 8
same thing. but its easy to change y=b+mx to y=mx+b
The x in y=mx+b is the independent variable. You could solve for x, making this a function of y, with simple algebra. y = mx + b y - b = mx (y-b)/m = x