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Eight years ago Sam was eight times the age of his son Sam Jr - Today if you add their ages together they add up to 52 How old are sam and his sun?
Sam is 40 and Sam Junior is 12.
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In two equations in the past:
Let S = Sam and J = Junior
S + J = 52
S + J = 36 (52-16)
S = 8J
so 9J = 36, J was 4, and S was 32
Today, Sam is 40 and J is 12
Eight years ago, (40-8) = 8 (12-8), 32 = 8 x 4
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In two equations in the present:
S + J = 52
S - 8 = 8 (J - 8)
and
(52 - J) - 8 = 8 (J - 8)
44 - J = 8J - 64
44 = 9J - 64
108 = 9J and J = 12, S = 40
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Answer 3Assume the father age is S and the son age is J
Then :
S + J = 52 ............................................................. (1)
(S-8) = 8 x (J-8)
S - 8J = 8 - 64
S - 8J = - 56 .............................................................(2)
Subtracting eqn (2) from eqn (1) gives:
9J = 108
J = 12 years
Substituting in eqn (1) with J = 12 gives S = 52 - 12 = 40 years
J = 12 and S = 40
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