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Eight times
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What is 1280 as a product of its prime factors?
It is: 2^8 times 5 = 1280
What is 1280 as the product of its prime number?
It is: 2*2*2*2*2*2*2*2*5 = 1280 or as 2^8 times 5 = 1280
How do you express as a product of its prime factors 1280?
As a product of its prime factors: 2*2*2*2*2*2*2*2*5 = 1280 or as 2^8*5 = 1280
What is the product of 1280 of its prime factor?
As a product of its prime factors: 2*2*2*2*2*2*2*2*5 = 1280 Or as: 2^8 times 5 = 1280
What is the next number of this pattern 5 20 80 320?
It is 4 times 320 = 1280
How many times do you have to double 5 to get to a million?
18
What times what times what equals 1280?
(160 × 8), (256 × 5), (320 × 4), (640 × 2)
What is 1280 as a product of it's prime numbers?
2^8 x 5 = 1280
What are the prime factors of 1280?
(including each only once) 2, 52^8 x 5 = 1280
What will be the first term and the common ratio of geometric progression whose 6th and 9th terms are 160 and 1280 respectively?
To find the first term and common ratio of a geometric progression, we can use the formula for the nth term of a geometric sequence: (a_n = a_1 \times r^{(n-1)}). Given that the 6th term is 160 and the 9th term is 1280, we can set up two equations using these values. From the 6th term, we get (a_1 \times r^5 = 160), and from the 9th term, we get (a_1 \times r^8 = 1280). By dividing the two equations, we can eliminate (a_1) and solve for the common ratio (r).
What are all the factors of 1280?
The factors of 1280 are: 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 64, 80, 128, 160, 256, 320, 640, 1280.
What are the factors of 1280?
The positive integer factors of 1280 are: 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 64, 80, 128, 160, 256, 320, 640, 1280
