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t=(square root of)(2d/g)

t=2(78.4)/9.8

t=156.8/9.8

t=(square root of)16

t=4 seconds

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t=(square root of)(2d/g)

t=2(78.4)/9.8

t=156.8/9.8

t=(square root of)16

t=4 seconds

t=(square root of)(2d/g)

t=2(78.4)/9.8

t=156.8/9.8

t=(square root of)16

t=4 seconds

time is 1.5 second

building is about 78 m high.

Answer: 78.4 meters

40 m/s [V=u + at = 0 + 10*4]

Q: A ball is thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff How high was the cliff?

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If it was thrown horizontally or dropped, and hit the ground 3.03 seconds later, then it hit the ground moving at a speed of 29.694 meters (97.42-ft) per second. If it was tossed at any angle not horizontal, and hit the ground 3.03 seconds later, we need to know the direction it was launched, in order to calculate the speed with which it hit the ground.

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False, provided the drop occurs no sooner than the throw, and the ground is flat .

No. They both hit the ground at the same time, because the VERTICAL component of velocity in both cases is the same.

No. They both hit the ground at the same time. This is because the VERTICAL component of velocity in both cases is the same.

Related questions

The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.

10 m/s

Answer: 3 seconds

64 METERSA+

If it was thrown horizontally or dropped, and hit the ground 3.03 seconds later, then it hit the ground moving at a speed of 29.694 meters (97.42-ft) per second. If it was tossed at any angle not horizontal, and hit the ground 3.03 seconds later, we need to know the direction it was launched, in order to calculate the speed with which it hit the ground.

Answer: 44 meters

64 metersIf a ball is thrown horizontally at 20 m/s from the top of a cliff that is 50 meters high, the ball will strike the ground 64 m from the base of the cliff (20m/s x 3.2 s).

"3.2" or "3.20" please put all of that

If it was thrown horizontally, it had an initial velocity of 10 meters/sec parallel to the ground. (It traveled 40 meters in 4 secs with no acceleration. x=vt) It also took 4 secs to travel vertically. It started with a vertical velocity of 0 m/s. Using x=v0 + (1/2) a t2 a = -g ( Acceleration due to gravity 9.8m/s2) x=0-(1/2)g*16 = -8 * 9.8 = -78.4 m It fell 78.4 meters before coming to a stop.

22.35294117647059

It doesn't matter whether the object is thrown down, up, horizontally, or diagonally. Once it leaves the thrower's hand, it is accelerated downward by an amount equal to acceleration of gravity on the planet where this is all happening. On Earth, if you throw an object horizontally, it accelerates downward at the rate of 9.8 meters per second2 ... just as it would if you simply dropped it. Whether it's dropped or thrown horizontally, it hits the ground at the same time.

yes, i just test right now