0
What else can I help you with?
If an car has a mass of 400 kg and a velocity of 30ms to the east what is the magnitude of its momentum?
The momentum of the car is given by the formula: momentum = mass x velocity. Plugging in the values, the momentum of the car is 400 kg x 30 m/s = 12000 kg*m/s.
A body of mass 2kg is moving with a uniform speed of 30ms-¹ a force of 6N is appiled against the direction of motionhow much distance with the body move in 5second after that?
The force applied will decelerate the body. The acceleration can be calculated using the equation F = ma, where F is the force, m is the mass, and a is the acceleration. In this case, the acceleration will be -3 m/s^2 (negative because it's in the opposite direction to the velocity). Using the equation v = u+at, where v is final velocity, u is initial velocity, a is acceleration, and t is time, you can find the final velocity after 5 seconds. Finally, use the equation s = ut + 0.5at^2 to find the distance moved after 5 seconds.
Calculate a car goes from 20ms to 30ms in 10 seconds. what is its acceleration?
The car's acceleration can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Plugging in the values, we get: (30 m/s - 20 m/s) / 10 sec = 1 m/s^2. The car's acceleration is 1 meter per second squared.
A ball is shot out of a cannon with initial velocity 30ms at 30 degree above the horizontal. How long is ball in the air How far away from the cannon does the ball hit What the max height by ball?
The time the ball is in the air can be found using the vertical motion equation: time = 2 * (initial vertical velocity) / (gravity). The range can be calculated using the horizontal motion equation: range = (initial velocity)^2 * sin(2*launch angle) / gravity. The maximum height can be determined by finding the vertical component of the flight time and substituting that into the vertical motion equation: max height = (initial vertical velocity)^2 / (2 * gravity).
How much energy is required in changing the velocity of an object of mass 5000kg from 20ms to 30ms?
Initial kinetic energy = 1/2 M Vi2 Final kinetic energy = 1/2 M Vf2 Difference = 1/2 M (Vf2 - Vi2) = 2,500(302 - 202) = 2,500(900 - 400) = 2,500 x 500 = 1,250,000 joules
A 500kg truck moving a 30ms strikes a parked car and they connect together and move forward what is the speed of the car and truck as they move forward connected together?
Momentum = mass x velocity. You already stated the mass and velocity so you can figure out the momentum.
If an car has a mass of 400 kg and a velocity of 30ms to the east what is the magnitude of its momentum?
The momentum of the car is given by the formula: momentum = mass x velocity. Plugging in the values, the momentum of the car is 400 kg x 30 m/s = 12000 kg*m/s.
When body have 2ms accleration in 15 seconds with a velocity 30ms does the velocity of the car uniform?
Although the question is stated in a somewhat confusing way, we can state withconfidence that the velocity of the car is NOT uniform, because a value is given forits acceleration. 'Uniform' motion means zero acceleration.
A 500kg truck moving at 30ms strikes a parked 300kg car they connect together and move forward what is the speed of the car and truck as they move forward connected together after the collision?
A Lot!
A body of mass 2kg is moving with a uniform speed of 30ms-¹ a force of 6N is appiled against the direction of motionhow much distance with the body move in 5second after that?
The force applied will decelerate the body. The acceleration can be calculated using the equation F = ma, where F is the force, m is the mass, and a is the acceleration. In this case, the acceleration will be -3 m/s^2 (negative because it's in the opposite direction to the velocity). Using the equation v = u+at, where v is final velocity, u is initial velocity, a is acceleration, and t is time, you can find the final velocity after 5 seconds. Finally, use the equation s = ut + 0.5at^2 to find the distance moved after 5 seconds.
Two buses depart from Chicago and going to New York and one to San Francisco. Each bus travels at a speed of 30ms. Do these buses have equal velocities explain.?
No the two buses do not have equal velocities because VELOCITY is the SPEED in a given DIRECTION. One would have a velocity of +30m/s because it is traveling in one direction, and the other would have a velocity of -30m/s because it is traveling in the opposite direction.
A car accelerates from rest and accelerates at 3 ms-2 how long it will take to reach a velocity of 30ms-1?
Acceleration = (change in speed) / (time for the change)3 = (30) / (time)3 x (time) = 30time = 30/3 = 10 seconds
Calculate a car goes from 20ms to 30ms in 10 seconds. what is its acceleration?
The car's acceleration can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Plugging in the values, we get: (30 m/s - 20 m/s) / 10 sec = 1 m/s^2. The car's acceleration is 1 meter per second squared.
A car is moving at a constant speed of 30ms the combined mass of the car and the driver is 1000kg if the driving force is 3000N what is the value of the frictional force?
If the car and driver are moving (along a flat horizontal surface) at constant speed, then there is no acceleration, and the net horizontal force is zero.The applied 3,000N must be canceled by an effective total 3,000N of friction.
A ball is shot out of a cannon with initial velocity 30ms at 30 degree above the horizontal. How long is ball in the air How far away from the cannon does the ball hit What the max height by ball?
The time the ball is in the air can be found using the vertical motion equation: time = 2 * (initial vertical velocity) / (gravity). The range can be calculated using the horizontal motion equation: range = (initial velocity)^2 * sin(2*launch angle) / gravity. The maximum height can be determined by finding the vertical component of the flight time and substituting that into the vertical motion equation: max height = (initial vertical velocity)^2 / (2 * gravity).
A 500kg truck moving a 30ms strikes a parked car with a mass of 300kg?
It is a perfectly inelastic collision.Types of collisions:* Perfectly inelastic- collision in which two objects stick together after the collision so that their final velocities are the same. * Elastic-collision in which the two objects bounce after the collision so that they move separately * Inelastic-collision in which the two objects deform during the collision so that the total kinetic energy decreases , but the objects move separately after the collision.
How far can a xbox 360 wifi reach?
The new wireless N adapter for Xbox 360 can work effectively from 50-100 feet, however, there is some notable lag-time of about 20-30ms.
