No. It depends on the amount of space the object occupies, which is known as its "volume".
Within that volume, it may have a large mass, a small mass, or an in-between mass, depending on
what substance comprises the object. In each case, it would displace the same amount of liquid.
In fact, where the question uses the slippery word "amount", it's really talking about "volume" of liquid.
Volume by displacement is a method used to measure the volume of irregularly shaped objects by submerging them in a liquid-filled container and measuring the amount of liquid displaced. The volume of the object is equal to the volume of liquid displaced, as per Archimedes' principle.
Displaced liquid refers to the volume of liquid that is pushed aside or moved when an object is submerged or immersed in the liquid. This concept is related to Archimedes' principle, which states that the buoyant force acting on an object is equal to the weight of the displaced liquid.
The weight loss of an object when immersed in a liquid is due to the buoyant force acting on the object. This force is equal to the weight of the liquid displaced by the object. As a result, the apparent weight of the object is reduced when immersed in a liquid.
The density of a liquid affects the buoyancy of objects placed in it according to Archimedes' principle. When an object is immersed in a liquid, the buoyant force acting on it is equal to the weight of the liquid displaced by the object. Therefore, if the liquid has a higher density, it can support more weight and provide greater buoyant force. Conversely, a less dense liquid will provide less buoyant force for the same volume of liquid displaced.
To calculate the mass of the hydrometer, you need the volume of the liquid displaced by the hydrometer. Since the density of the liquid is 0.80 g/cm³ and the depth is 7.5 cm, the volume of the liquid displaced would be 7.5 cm³. You can then calculate the mass by multiplying the volume of liquid displaced by the density of the liquid.
Volume by displacement is a method used to measure the volume of irregularly shaped objects by submerging them in a liquid-filled container and measuring the amount of liquid displaced. The volume of the object is equal to the volume of liquid displaced, as per Archimedes' principle.
I would place it in a container full of liquid after measuring the liquid. I would measure the amount of liquid displaced by the object. That amount is equal to the volume of the irregular object if it is fully submerged in the liquid.
he discovered that volume of object immersed in water =volume of liquid displaced
The volume of liquid displaced has the same mass as the floating object.
Displaced liquid refers to the volume of liquid that is pushed aside or moved when an object is submerged or immersed in the liquid. This concept is related to Archimedes' principle, which states that the buoyant force acting on an object is equal to the weight of the displaced liquid.
I would place it in a container full of liquid after measuring the liquid. I would measure the amount of liquid displaced by the object. That amount is equal to the volume of the irregular object if it is fully submerged in the liquid.
It doesn't matter how much of the liquid you have and it is a characteristic property.
I think you mean a buoyant force. When an object is submerged into a liquid, the liquid pushes up on the object with a force equal to the weight of the amount of fluid that is displaced.
Two ways to do this: 1) Floating the less dense object on the more dense liquid. To verify the Archimedes principle you need to show that the mass of the liquid displaced by the less dense object is equal to the mass of the less dense object. To do this you need to have a way to determine the mass of the displaced liquid. If the liquid is in a container filled to the brim, then when you place the less dense object in it, the displaced liquid will spill out over the edges of the container. If you can collect and weight that liquid, then you can compare its weight to the weight of the less dense object - they should match. Alternatively, you can find a way to measure the volume of the displaced liquid and calculate the mass from the volume and density of the displaced liquid. 2) Immerse the object completely in the liquid and measure the force required to keep it submerged. This one is more complicated and difficult to execute and measure. The force required to keep the less dense object submerged should be the difference between the weight of the object (when it is not in the liquid) and the weight of the displaced liquid.
It depends on the objects' volume. Different objects that have the same volume, if submerged, experience the same buoyancy. The buoyancy is equal to the weight of the displaced liquit; in other words, volume (of submerged object, or of the submerged part) x density of the liquid x gravity.
The weight loss of an object when immersed in a liquid is due to the buoyant force acting on the object. This force is equal to the weight of the liquid displaced by the object. As a result, the apparent weight of the object is reduced when immersed in a liquid.
The density of a liquid affects the buoyancy of objects placed in it according to Archimedes' principle. When an object is immersed in a liquid, the buoyant force acting on it is equal to the weight of the liquid displaced by the object. Therefore, if the liquid has a higher density, it can support more weight and provide greater buoyant force. Conversely, a less dense liquid will provide less buoyant force for the same volume of liquid displaced.