The answer will be 5 m/sec/sec
300m/sec - 200m/sec divided by 20 seconds will get you 100m/sec divided by 20 seconds, which then equals 5
The acceleration of the car is calculated using the formula: acceleration = (final velocity - initial velocity) / time. Plugging in the given values, the acceleration of the car is (20 m/s - 5 m/s) / 3 s = 5 m/s^2.
The acceleration of the car can be calculated using the formula ( \text{acceleration} = \frac{\text{change in velocity}}{\text{time taken}} ). In this case, the change in velocity is 20 m/s - 5 m/s = 15 m/s, and the time taken is 3 s. Therefore, the acceleration of the car is ( \frac{15 \text{ m/s}}{3 \text{ s}} = 5 \text{ m/s}^2 ).
The car's acceleration is 5 m/s^2. This is calculated by dividing the change in velocity (20 m/s - 5 m/s = 15 m/s) by the time it took to change (3 s).
The acceleration of the car can be calculated using the formula: acceleration = change in velocity / time. In this case, the change in velocity is 20 - 5 = 15 miles per second. So, the acceleration is 15 miles per second / 3 seconds = 5 miles per second squared.
The acceleration of the object is 20 m/s^2. This is because acceleration is defined as the change in velocity per unit time, and in this case the object's speed is increasing by 20 m/s every second of fall.
Acceleration = change in speed/time = (20-5)/3 = 15/3 = 5 units of speed per second. It is not possible to be any more precise because the unit of speed (kilometres per hour, miles per hour, metres per second) is unspecified.
Average acceleration = (change in speed) divided by (time for the change)= (80) / (20) = 4 meters per second2
The acceleration of the car is calculated using the formula: acceleration = (final velocity - initial velocity) / time. Plugging in the given values, the acceleration of the car is (20 m/s - 5 m/s) / 3 s = 5 m/s^2.
Assuming that acceleration is constant during that time, just divide the change in speed by the time.
The acceleration of the car can be calculated using the formula ( \text{acceleration} = \frac{\text{change in velocity}}{\text{time taken}} ). In this case, the change in velocity is 20 m/s - 5 m/s = 15 m/s, and the time taken is 3 s. Therefore, the acceleration of the car is ( \frac{15 \text{ m/s}}{3 \text{ s}} = 5 \text{ m/s}^2 ).
well we know that we have two speeds and a time. So, initial speed = 80 final speed = 60 change in time = 6 Now acceleration in this case will be measured in kilometers per hour per second (i.e. every x seconds, y kilometers per hour are gained in speed) So we simply apply the formula Acceleration = (final speed - initial speed)/ change in time = (80 - 60)/6 = 20/6 = 3.6666667 km/h/s
Magnituide of acceleration = (change in speed) divided by (time for the change)= (final speed - initial speed) divided by (time for the change)= 2/20 = 0.1 meter per second2Note that this is the magnitude of the acceleration, obtained by working with the speeds.We don't know the initial or final velocities, because there's no information regarding directions.Similarly, we only know the magnitude of the acceleration, not its direction.
It increases by 20 centimetres per second in the given direction for each second that elapses.
The car's acceleration is 5 m/s^2. This is calculated by dividing the change in velocity (20 m/s - 5 m/s = 15 m/s) by the time it took to change (3 s).
20 meters per second. This is because the acceleration due to gravity is equal to 20 meters per second per second, meaning the object's speed increases by 20 meters per second for each second of free fall.
Acceleration = Change in speed/Time Time = Change in Speed/Acceleration = 65mph/20mph per s = 65/20 seconds = 3.25 seconds
The acceleration of the car can be calculated using the formula: acceleration = change in velocity / time. In this case, the change in velocity is 20 - 5 = 15 miles per second. So, the acceleration is 15 miles per second / 3 seconds = 5 miles per second squared.