torque
The work done is 84 Joules (Work = Force x Distance).
Work is the transfer of energy that occurs when a force is applied to an object and the object is displaced in the direction of the force. The unit of work is the joule (J), which is equivalent to a force of one newton acting over a distance of one meter.
The work done by the force is calculated as force times distance, which is 1 newton * 2 meters = 2 joules. Power is the rate at which work is done, so in this case, power is 2 joules / 1 second = 2 watts.
When a force of 2N moves an object 3 meters, the work done is 6 Joules (2N * 3m). When a force of 3N moves an object 2 meters, the work done is 6 Joules as well (3N * 2m). Consequently, the same amount of work (6 Joules) is done in both scenarios.
torque
The work done is 84 Joules (Work = Force x Distance).
Work is the transfer of energy that occurs when a force is applied to an object and the object is displaced in the direction of the force. The unit of work is the joule (J), which is equivalent to a force of one newton acting over a distance of one meter.
A rocket that travels 9000 meters in 12.12 seconds moves at 742.5742 meters/second which is approx 1660 mph
If an object moves 50 meters in 5 seconds, its average speed is 50/5 = 10 meters per second.
Work = (force) x (distance) = (20n) x (2m) = 40 newton-meters = 40 joules.
The work done by the force is calculated as force times distance, which is 1 newton * 2 meters = 2 joules. Power is the rate at which work is done, so in this case, power is 2 joules / 1 second = 2 watts.
When a force of 2N moves an object 3 meters, the work done is 6 Joules (2N * 3m). When a force of 3N moves an object 2 meters, the work done is 6 Joules as well (3N * 2m). Consequently, the same amount of work (6 Joules) is done in both scenarios.
20 meters per second
The work done on the object is calculated using the formula Work = Force x Distance. In this case, the work done is 50 N (force) x 15 m (distance) = 750 joules.
The work done is 60 Joules (12 N * 5 m) when a force of 12 Newton moves an object a distance of 5 meters. Work is calculated by multiplying the force applied by the distance over which it is applied in the direction of the force.
In order to stop the car within 5 seconds, it must have a negative acceleration (or deceleration) of -2m/s2. According to Newton's 2nd law: F = m*a. a = -2, m = 900kg, so F must be -1800N. Or 1800 Newtons to the direction reversed to the movement.