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Ignoring air resistance, it's about 9.8 m/s.

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13y ago
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6mo ago

The skydiver's downward velocity after 1 second can vary, but on average it is around 9.8 m/s, the acceleration due to gravity. This value can change based on various factors such as air resistance, body position, and altitude.

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Q: What is the skydiver's downward velocity after 1 second?
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What is the skydivers forward velocity after 1 second?

The skydiver's forward velocity after 1 second would depend on factors such as their body position, weight, and air resistance. On average, a skydiver in freefall might reach a forward velocity of around 120 mph (193 km/h) after 1 second.


What is the skydiver velocity aftter one second show your work and include direction?

Assuming the skydiver starts at rest and accelerates at a rate of 9.8 m/s^2 due to gravity, the velocity after one second would be 9.8 m/s downward. This is because velocity is the initial velocity of 0 m/s plus the acceleration of 9.8 m/s^2 multiplied by 1 second.


A ball is thrown upward from the ground with a speed of 36.0 ms At what time after being thrown does the ball have a velocity of zero?

The ball reaches a velocity of zero when it reaches its highest point in its trajectory. This occurs when the ball's vertical velocity decreases to zero before changing direction and becoming negative as it falls back down. The time it takes for the ball to reach this point can be calculated using the kinematic equation (v_f = v_i + at), where (v_f = 0) m/s, (v_i = 36.0) m/s, and the acceleration due to gravity (a = -9.81) m/s(^2). By substituting in these values, you can solve for (t), the time taken for the velocity to reach zero.


What is the change in velocity during the 2-s interval from 1 s before the highest point to 1 s after the highest point?

The velocity at the highest point of motion is zero, so the change in velocity from 1 second before to 1 second after is the final velocity after the highest point minus the initial velocity before the highest point. Since velocities at these points have opposite signs, the magnitude of the change in velocity would be the sum of the speeds at the corresponding points.


What is the distance covered by an object in last one second of its motion?

The distance covered by an object in the last second of its motion is equal to the object's velocity in meters per second. This means that if the object is moving at a constant velocity, the distance covered in the last second will be the same as the velocity.

Related questions

What is a skydivers downwords velocity after 1 second when falling from a hovering helicopter?

Neglecting air resistance his velocity after 1 second will be 9.81 m/sec or 32.2 ft/sec.


What is the skydivers forward velocity after 1 second?

The skydiver's forward velocity after 1 second would depend on factors such as their body position, weight, and air resistance. On average, a skydiver in freefall might reach a forward velocity of around 120 mph (193 km/h) after 1 second.


What is the skydiver's upward velocity after 1 second?

I presume you mean 1 second after jumping from the plane. Since skydiver's fall, their velocity is generally in a downward direction, so the upward velocity is negative. The formula v = gt, where g is the acceleration due to gravity which is about 32.2 feet per second per second, tells us that after 1 second it would be about -32.2 feet per second.


What is the skydiver velocity aftter one second show your work and include direction?

Assuming the skydiver starts at rest and accelerates at a rate of 9.8 m/s^2 due to gravity, the velocity after one second would be 9.8 m/s downward. This is because velocity is the initial velocity of 0 m/s plus the acceleration of 9.8 m/s^2 multiplied by 1 second.


How does velocity varies with the vertical distance traveled by the object?

When an object falls vertically downward, its velocity increases according to the following equation:2aS=vf2 - vi2 or ,2*10*S=v2, orv=(20S)1/2.There is a second case in which a body is thrown vertically upward, here its velocity decreases as it moves upward. Here its velocity becomes zero as it reaches the highest point


A banana is thrown straight out so it has both horizontal and vertical velocity After 1 second, what is its vertical velocity?

9.8


How can velocity be expressed in units?

metres per second ms-1


A ball is thrown upward from the ground with a speed of 36.0 ms At what time after being thrown does the ball have a velocity of zero?

The ball reaches a velocity of zero when it reaches its highest point in its trajectory. This occurs when the ball's vertical velocity decreases to zero before changing direction and becoming negative as it falls back down. The time it takes for the ball to reach this point can be calculated using the kinematic equation (v_f = v_i + at), where (v_f = 0) m/s, (v_i = 36.0) m/s, and the acceleration due to gravity (a = -9.81) m/s(^2). By substituting in these values, you can solve for (t), the time taken for the velocity to reach zero.


What is the unit of velocity in SI unit system?

The unit of velocity in the SI unit system is meters per second (m/s).


When a ball is thrown vertically upward at initial velocity of 15 meter per second Find the position and velocity after 1.0 second and 40 second after leaving your hand?

1 sec : position = 10.1 metres above your hand, velocity = 5.2 ms^-1.40 sec : position = 7240 metres below your hand, velocity = 377 ms^-1 downwards.


What is the change in velocity during the 2-s interval from 1 s before the highest point to 1 s after the highest point?

The velocity at the highest point of motion is zero, so the change in velocity from 1 second before to 1 second after is the final velocity after the highest point minus the initial velocity before the highest point. Since velocities at these points have opposite signs, the magnitude of the change in velocity would be the sum of the speeds at the corresponding points.


An angry construction worker throws his wrench downward from a height of 128 feet with an initial velocity of 32 feet per second. The height of the wrench above the ground after 1 second is what?

s=u*t +1/2*a*t*t u=32 t=1 a=33 s=48.5 hence height above ground=128-48.5 =79.5 feet