13 x 43
Let x be the first integer. Then the sum of the three consecutive integers is x + (x+1) + (x+2), which equals 3x + 3. We are given that this sum is 43, so we can write the equation 3x + 3 = 43. Solving this equation, we find that x = 13. Therefore, the three consecutive integers are 13, 14, and 15.
39 = 3 x 13 49 = 7 x 7 51 = 3 x 17 43 is prime 31 is prime
13 is 30.233% of 43. (rounded)
1 x 43, 43 x 1
13-3x = 43 -3x = 43-13 -3x = 30 x = -10
x + y = 43 x - y = 13 2x = 56 x = 28 28 + y = 43 y - 28 = 43 = 15 I'm sure you meant: y = 43 - 28 = 15
13 x 43
x = 13 x 12 + 1 = 43 x 1 + 1 = 43 + 1 = 44 = 4
Sesame Street - 1969 The Very End of X 43-13 was released on: USA: 21 November 2012
1 x 2236, 2 x 1118, 4 x 559, 13 x 172, 26 x 86, 43 x 52, 52 x 43, 86 x 26, 172 x 13, 559 x 4, 1118 x 2, 2236 x 1
13 x 3 = 39 so it is 3 with 4 left over (43 - 39 = 4) 3.4/13 or 3-4/13 Three and four-thirteenths
Let x be the first integer. Then the sum of the three consecutive integers is x + (x+1) + (x+2), which equals 3x + 3. We are given that this sum is 43, so we can write the equation 3x + 3 = 43. Solving this equation, we find that x = 13. Therefore, the three consecutive integers are 13, 14, and 15.
39 = 3 x 13 49 = 7 x 7 51 = 3 x 17 43 is prime 31 is prime
43 greater than x - 43+x 43 greater than x plus 35 - 43+x+35 43+35+x=78+x
13/6 x 20 = 260/6 = 130/3 = 43 and 1/3
286 = 2 x 11 x 13