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13 x 43
Let x be the first integer. Then the sum of the three consecutive integers is x + (x+1) + (x+2), which equals 3x + 3. We are given that this sum is 43, so we can write the equation 3x + 3 = 43. Solving this equation, we find that x = 13. Therefore, the three consecutive integers are 13, 14, and 15.
39 = 3 x 13 49 = 7 x 7 51 = 3 x 17 43 is prime 31 is prime
13 is 30.233% of 43. (rounded)
1 x 43, 43 x 1