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Let x be the first integer. Then the sum of the three consecutive integers is x + (x+1) + (x+2), which equals 3x + 3. We are given that this sum is 43, so we can write the equation 3x + 3 = 43. Solving this equation, we find that x = 13. Therefore, the three consecutive integers are 13, 14, and 15.
43, 44, 45
It is 42 because 42+43+44 = 129
The numbers are 41, 43 and 45.
They are: -39 -41 -43 = -123
Those three odd integers are 43, 45, and 47.