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A line with slope of one and a half that passes through the point 2 and -1.?
Wiki User
∙ 14y ago
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Lorine Boyle
Wiki User
∙ 14y agoThe standard formula for a straight line is y = ax + b.
The slope is given as 1½ = 3/2 therefore we now have y = 3x/2 + b.
When y = -1, x = 2 substituting for these in the equation gives :-
-1 = 6/2 + b : -1 = 3 + b : b = -4
The equation for the line becomes : y = 3x/2 - 4
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If the point is x=a, y=b, the line is (y-b)=slope times (x-a).Or, slope=(y-b)/(x-a)So (y+1/2)=1/2 (x-1/3)Another answer:-Point: (1/3, -1/2)Slope: 1/2Equation: y - -1/2 = 1/2(x -1/3) => y = 1/2x -2/3In its general form: 3x -6y -4 = 0
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