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A train starting from rest attains a velocity of 72Km hr in 5 minutes. Assuming that the acceleration is uniform what is the distance travel by train while attained the velocity?
Wiki User
∙ 7y ago
As the acceleration is uniform, the train has an average speed that is half the difference between the start and final velocities, which in this case is half the final velocity.
1 hr = 60 min
1 km/h = 1 km ÷ 1 hr
= km ÷ 60 min
= 1/60 km/min
Distance = velocity × time
= (½ × 72 × 1/60 km/min) × (5 min)
= 36/60 × 5 km
= 3 km
Wiki User
∙ 7y ago
Wiki User
∙ 7y ago3 kilometres.
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What is the formula for distance traveled in acceleration?
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How do you find the time from acceleration and distance?
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Look at the metric ruler pictured Assuming that 0 is visible on the measure and is also the starting pointwhat is the distance to point D?
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Why is acceleration measured in meters seconds squared?
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