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Perimeter and area are not sufficient to determine the shape of a figure.
Yes.
Yes
a 4*5 rectangle.
Even if you knew how many sides the polygon has, you stillcould not calculate its perimeter with that much information.Examples:-- An equilateral triangle with area of 20 has perimeter of 20.3885 .-- A square with area of 20 has perimeter of 17.889(rounded).-- A rectangle with area of 20 can have any perimeter more than 17.889 .4 by 5 . . . . area = 20, perimeter = 182 by 10 . . . area = 20, perimeter = 241 by 20 . . . area = 20, perimeter = 42..etc.
Perimeter and area are not sufficient to determine the shape of a figure.
yes, for example: a 4 by 5 rectangle has an area of 20 and a perimeter of 18 a 2 by 7 rectangle has an area of 14 and a perimeter of 18 they both have a perimeter of 18
Yes if you
Yes.
Yes
Yes.
a 4*5 rectangle.
Actually it is possible.
Even if you knew how many sides the polygon has, you stillcould not calculate its perimeter with that much information.Examples:-- An equilateral triangle with area of 20 has perimeter of 20.3885 .-- A square with area of 20 has perimeter of 17.889(rounded).-- A rectangle with area of 20 can have any perimeter more than 17.889 .4 by 5 . . . . area = 20, perimeter = 182 by 10 . . . area = 20, perimeter = 241 by 20 . . . area = 20, perimeter = 42..etc.
4cm x 5cm
Perimeter: 2(4+5) = 18 units Area: 4*5 = 20 square units
To find the width of the rectangular field, use the formula for area: Area = Length × Width. Given that the area is 20 sq.m and the length is 5 m, the width can be calculated as Width = Area / Length = 20 sq.m / 5 m = 4 m. The perimeter of a rectangle is given by the formula Perimeter = 2(Length + Width), which in this case is Perimeter = 2(5 m + 4 m) = 18 m. Therefore, the width is 4 m and the perimeter is 18 m.