The average of the three numbers 6, 789 and 10 is 268.33 recurring.
It is: 6+4+4+10 = 24 and 24/4 = 6 which is the average
You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...
(14 + 6) ÷ 2 = 10 Therefore, the mean (average) is 10.
7 = average of 6 and 8
The average is 10.
Average = (6 + 10 + 56 + 8)/4 = 20
The average of the three numbers 6, 789 and 10 is 268.33 recurring.
It is: 6+4+4+10 = 24 and 24/4 = 6 which is the average
You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...
10
Average = (6+9+10+11)/4 = 36/4 = 9
The mean average is (6+12+10+4+3)÷5 = 7 The median average is middle number of {3, 4, 6, 10, 12} = 6 There is no mode average as every number appears with the same frequency (of 1).
The average is 8
The mean (or average) of 6 and 10 is1/2 (6 + 10) = 8
It can be anywhere between 2 and 10. It's usually around 6 though.
The answer to average of 6 10 56 and 104 would be 44