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B squared plus 20b equals -80?
Use quadratic equation. I will go thru this one step at a time.
b^2 + 20b = -80 ..add +80 to both sides
b^2 + 20b +80 = 0
General quadratic equation
ax^2 +bx + c = 0
x = [-b ± (b^2 - 4*a*c)^0.5] ÷ 2*a
In your equation
a =1
b = 20
c = 80
Substituting these values into the general equation:
x = [-20 ± (20^2 - 4*1*80)^0.5] ÷ 2*1
x = [-20 ± (400 - 320)^0.5] ÷ 2
x = [-20 ± 80^0.5] ÷ 2
X1 = [-20 + 80^0.5] ÷ 2
X2 = [-20 - 80^0.5] ÷ 2
I got X1 = -5.528 and X2 = -14.47
Or go to a quadratic equation solver web site such as
http://www.math.com/students/calculators/source/quadratic.htm
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