Yes.
Split it down the line joining the midpoints of the sides of length 6 ft to create 2 rhombuses both with sides of length 3 ft.
Yes, it can.
It is when you divide an object or number into two equal numbers/segments. For example, cutting a pizza in half will give you two congruent parts. If a human was symmetrical, and you sliced them down the middle you would have two congruent parts.
Corresponding; congruous.Mathematics.Coinciding exactly when superimposed: congruent triangles.Of or relating to two numbers that have the same remainder when divided by a third number. For example, 11 and 26 are congruent when the modulus is 5.This was taken directly from the American Heritage Dictionary
Yes. Since a parallelogram can be divided into two triangles, and since we know that the angles of every triangle add to 180 degrees, then twice 180 is 360.
Yes into 10 inches by 10 inches squares
a quadrilateral isa polygon with four sides and four vertices. Sometimes the word quadrangle is used. The interior angles add up to 360 degrees. Quadrilaterals are either simple (not self- intersecting) or complex (self-intersecting). Quadrilaterals and polygons in general, are broadly divided into two groups: convex and concave polygon.
Yes, the diagonal splits the parallelogram into two equal triangle aka congruent the sides will stay the same, the two angles being divided are going to be split in half, one on each side, so its the same
Yes. Read on for why: Take a parallelogram ABCD with midpoints E and F in the bases. So something like this (forgive the "drawing"): A E B __.__ /__.__/ C F D We know that parallelogram AEFC = EBDF, since they have the same base (F bisects CD, so CF = FD), height (haven't touched that), and angles (<ACF = <EFD because they're parallel - trust me that everything else matches). We also know that every parallelogram can be divided into two congruent triangles along their diagonal. So if two congruent parallelograms consistent of two congruent triangles each, then all four triangles are congruent. So your congruent triangles are ACF, AEF, EFD, and EBD. You can further reinforce this through ASA triangle congruency proofs (as I did at first), but this is a far more concise and equally valid answer.
Yes, into infinitely many sets of congruent rectangles. In fact, all plane shapes - including totally random ones - can be divided into sets of congruent shapes.
It is divided into two congruent triangles. Congruent means "the same size and shape" The triangles are right-angled with the other 2 angles each being 45 degrees. The sides opposite these 45 degree angles are two of the sides of the original square. If cut out, one triangle would fit exactly over the other one.
A trapezoid can be divided into 2 triangles but they are not normally congruent to each other.
Hopefully you've been given the parallelogram's area. If so you can use the following formula: Area of parallelogram = base length x altitude therefore altitude = area of parallelogram (divided by) base length
You would get two scalene triangles.
Infinitely many. Any rhombus can be divided into smaller rhombi, thereby increasing the total number.
Draw a square. Add the two diagonals. Draw lines from the midpoint of each side to the midpoint of the opposite side. You will now have a square divided into 8 congruent [isosceles, righ-angled] triangles
The opposite is separate, split, or disassemble.
A circle can.
Any plane triangle can be divided into four congruent triangles. Find the midpoint of each side, and draw a line from each midpoint to the other two midpoints. Forgive the crude ASCII graphics: <pre> + |\ + + | \ +-+-+ original triangle + |\ +-+ |\ |\ +-+-+ divided triangle + |\ +-+ each congruent triangle </ref>