Can you give me a program that will compute and display all the sum of odd numbers from 1-100?

Answer 1

101

Answer 2

First create a list of the number 0-100. (probably using for i in range(100) etc.)

Then run through this list checking if there is a remainder when you divide by 2.

(If there isn't a remainder the number is even. If there is then the number is odd.)

If there is a remainder of the number you are currently checking add it to a separate list.

You will then have a list of all the odd numbers.

Create a total that at first equals zero. Then run through the list of odd numbers constantly adding each one to the total.

At the end of this process the total will equal the sum of all of the odd numbers from 0 to 100.

Answer 3

printf ("sum of 1+3+...+97+99=%d\n", ((1+99)/2)*50);

1+2+...+99+100=5050

1+3+...+97+99=2500

2+4+...+98+100=2550

Answer 4

You won't directly find such a program here. That does sound suspiciously like a homework assignment. You might find someone who can give you some ideas, though.