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For the first step, express this as a difference of two squares, and use the corresponding formula. After factoring this, one of the two factors will again be the difference of two squares, and can be further factored.
Wiki User
∙ 9y ago
Wiki User
∙ 8y ago1 - 625z^4 =
(1 - 25z^2)(1 + 25z^2) =
(1 - 5z)(1 + 5z)(1 + 25z^2)
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Factor x4 - 81. Step 1: both numbers have square roots and have a minus sign between them so the first factor result is (x2+9)(x2-9). Step 2: (x2+9) does not factor, but (x2-9) factors to (x+3)(x-3). Step 3: Solution is (x2+9)(x+3)(x-3).
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I see only one step here. This is a difference of squares. The formula for that is a^2 - b^2 = (a + b)(a - b) Step one. Plug it in. (1 - 625^2)(1 + 625^2)
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idkrself find it you
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To determine if the only coomon factor of the numerator and denominator is 1 what is a good first step?
There is no good step. The fact that it is extremely difficult to establish that the only common factor is 1 is the basis of modern digital security.
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How do you completely factor x to the fourth power minus eighty one?
Factor x4 - 81. Step 1: both numbers have square roots and have a minus sign between them so the first factor result is (x2+9)(x2-9). Step 2: (x2+9) does not factor, but (x2-9) factors to (x+3)(x-3). Step 3: Solution is (x2+9)(x+3)(x-3).
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Scientific Method ?
