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2xy + 4x + 8y + 16

= 2[xy + 2x + 4y + 8]

= 2[x(y + 2) + 4(y + 2)]

= 2(y + 2)(x + 4)

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15y ago

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Wiki User

9y ago

2(x + 4)(y + 2)

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Q: Factor 2xy plus 4x plus 8y plus 16?
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