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( 2xy - 4x ) + ( 8y - 16)

2 ( xy - 2x ) + 2 ( 4y - 8 ) Answer

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Q: Factor 2xy - 4x plus 8y - 16?

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(2xy-4x)+ (8y-16)=2xy-4x+8y-16, which factors as 2(x+4)(y-2)

2xy - 4x plus 8y - 16 equals x plus 4 in parentheses multiplied by 2y minus 4 in parentheses. So, the factors are ( x + 4) and ( 2y - 4) .

4x2 - 4x + 2xy - 2y = 4x(x - 1) + 2y(x - 1) (4x + 2y)(x - 1).

2(x - 1)(2x + y)

2xy + 4x + 8y + 16 = 2[xy + 2x + 4y + 8] = 2[x(y + 2) + 4(y + 2)] = 2(y + 2)(x + 4)

2xy - 4x + 8y - 16 can be factored.(2xy - 4x) + (8y - 16)2x(y - 2) + 8(y - 2)Since y-2 is the same as the other, it would turn out like this:(2x + 8)(y - 2):]

They are four terms of an algebraic expression that can't be simplified

4x + 16 + 1 = 4x + 17 which cannot be factorised.

2 (2x2 + 2x + xy + y ) it's 2 (2x + y)(x + 1) if you're doing A+

4x2 - 4x + 2xy - 2y = 4x(x - 1) + 2y(x - 1) = (x - 1)(4x + 2y) = 2(x - 1)(2x + y)

4x-y2=2xy 2x ? y5 if its plus its 7 xy