-13
That factors to (2a - 7)(2a + 9)
a + a + a - 2a = 3a - 2a = a
2a + a = 3a
4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2
4a
What is the solution of -2a plus 3a plus 5b
8b -2a
x + 2a
(6ab + 9b)/(2a + 3) = 3b(2a + 3)/(2a + 3) = 3b
5a + 3 + (2a - 2) + a= 5a + 3 + 2a - 2 + a= 8a + 1
n2 - 4 is the "difference of two squares." That factors to (n - 2)(n+2)a2 + 2a + 1 is "additive squares." That factors to (a + 1)(a + 1) or (a + 1)2
2a-3+4b-2a-b-3+5=3b-1