(7x + 7)(x + 2) = 7x2 + 21x + 14
7*2+5=19 Check the order of operation.
Try 6!
x2 + 10x + 21 = (x + 3)(x + 7) You need to find 2 numbers which sum to 10 and whose product of 21. In this case 3 + 7 = 10 and 3 x 7 = 21.
sounds like 21: (7 x 2) is 14, plus 7 is 21
(7x + 7)(x + 2) = 7x2 + 21x + 14
7*2+5=19 Check the order of operation.
Try 6!
== ==
x2 + 10x + 21 = (x + 3)(x + 7) You need to find 2 numbers which sum to 10 and whose product of 21. In this case 3 + 7 = 10 and 3 x 7 = 21.
sounds like 21: (7 x 2) is 14, plus 7 is 21
Answer: 144Logic: Product of first number and sum of two numbers2+3 =10; 2*(2+3)7+2=63; 7*(7+2).....9+7=? 9*(9+7)= 9*16 = 144
When you find the product of something, it means you found the answer to a multiplication problem. For example 14 would be the product of 2 and 7.
#include<iostream> void product (double a, double b) { std::cout << "The product of " << a << " and " << b << " is " << a*b << std::endl; } int main () { product (6, 7); product (2, 21); } Output: The product of 6 and 7 is 42 The product of 2 and 21 is 42
To find the product you will multiply these numbers. You can do 7x16x43x12= on a calculator. The product is 57,792.
Since both 2 and 7 are prime, the LCM of 2 and 7 is simply their product, 14.
x2 + 4x - 21 = (x + 7)(x - 3). The trick is to find 2 numbers which sum to 4 and have a product of -21.