Here is how you can do that.1) First, use the usual procedure to find the least common multiple of that number.
2) Divide the smallest 4-digit number (1000) by the result of step 1. Round this number up to the nearest integer.
3) Multiply the least common multiple (from step 1) by the result of step 2.
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Ans: The number factorial 6 (which is 720) is divisible by 1 through 6; then, 720 + 1 = 721 is your number.
To find the smallest number divisible by both 12345678 and 9, we need to find the least common multiple (LCM) of the two numbers. The LCM is the smallest number that is a multiple of both 12345678 and 9. To calculate the LCM, we first need to find the prime factors of each number. The prime factorization of 12345678 is 2 x 3 x 47 x 14593, and the prime factorization of 9 is 3^2. The LCM is then the product of the highest power of each prime factor, which is 2 x 3^2 x 47 x 14593 = 12345678. Therefore, the smallest number divisible by both 12345678 and 9 is 12345678.
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A number which is divisible by both 2 & 3 is a multiple of 6 i.e. the number is divisible by 6.So, we need to find out the smallest 5 digit number divisible by 6(or 2 & 3).Smallest 5 digit number = 10000Dividing 10000 by 6, we get10000 = 6 x 1666 + 49996 = 6 x 1666If we add 6 to 9996 we obtain a number which is divisible by 6.6 + 9996 = 10002(divisible by 6).So, the smallest five digit number divisible by 6 is 10002.==========================================Here is another one that's smaller than 10,002 and satisfiesthe other specifications stated in the question:6.0000