It is not posssible to give an answer to this question because:
Finally, a linear equation represents a line, not a single point.
A linear equation is the equation of a line and that consists of an infnite number of points. What you have, in x = -4 and y = -1/3, is a single point. A single point is not a line and so there cannot be a linear equation (suitable for a line) to represent a point.
An Airy equation is an equation in mathematics, the simplest second-order linear differential equation with a turning point.
You don't. An equation with two variables can be graphed as a line or a curve on x-y coordinates. When you do that, EVERY point on the line or curve satisfies the equation. You can't 'solve' it ... i.e. come up with unique values for 'x' and 'y' ... until you have another equation. It represents another line or curve on the graph, and the 'solution' represents the point (or points) where the graphs of the two equations intersect.
This is a linear equation in two variables and the coordinates of each and every point on the line that it describes is a solution. A single linear equation does not have an "answer".
Linear means referring to a line, so a line must be linear! Every point on any line is a solution to the equation that defines the line.
It is a linear equation in the two variables x and y. A single linear equation in two variables cannot be solved for a unique pair of values of x and y. The equation is that of a straight line and any point on the line satisfies the equation.
Substitute the values for the two variables in the second equation. If the resulting equation is true then the point satisfies the second equation and if not, it does not.
The y-intercept of a linear equation is the point where the graph of the line represented by that equation crosses the y-axis.
The coordinates of the point of intersection represents the solution to the linear equations.
A linear equation is the equation of a line and that consists of an infnite number of points. What you have, in x = -4 and y = -1/3, is a single point. A single point is not a line and so there cannot be a linear equation (suitable for a line) to represent a point.
It's a single linear equation in two variables. The graph of the equation is a straight line; every point on the line is a set of values that satisfy the equation. In other words, there are an infinite number of pairs of (x,y) values that satisfy it. In order to figure out numerical values for 'x' and 'y', you would need another equation.
An Airy equation is an equation in mathematics, the simplest second-order linear differential equation with a turning point.
You don't. An equation with two variables can be graphed as a line or a curve on x-y coordinates. When you do that, EVERY point on the line or curve satisfies the equation. You can't 'solve' it ... i.e. come up with unique values for 'x' and 'y' ... until you have another equation. It represents another line or curve on the graph, and the 'solution' represents the point (or points) where the graphs of the two equations intersect.
A linear equation has a n infinite number of solutions. The coordinates of each point on the line is a solution.
Given a linear function in n variables, you need to select values for (n-1) of the variables. Solve the resulting function for the nth variable. Then the ordered n-tuple represents the coordinates, in n-dimensional space, of a point that is on the linear function.Selecting different sets of (n-1) variables, and different values will result in different solutions. Together, these will from a line in n-dimensional space.
This is a linear equation in two variables and the coordinates of each and every point on the line that it describes is a solution. A single linear equation does not have an "answer".
3s=2t can also be written as 3y=2x or 3x=2y. Either way, it is linear. To find out if it is linear, simply graph it. If you can draw a completely vertical line through any point of the graph without intersecting more than one point of the graph, then it is linear. This equation (3s=2t), it is linear.