One practical application of greatest common factor is to simplify fractions.
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It will enable you to reduce a ratio of two very large numbers to a ratio of more manageable ones. This is of particular importance if you want to carry out further calculations.
Euclid is the Greek mathematician who invented an easier way of finding the GCF.
Yes there is
When reducing fractions to their simplest form the greatest common factor of their numerator and denominator must be found.
True, and this property is useful for finding the greatest common factor (GCF) of two (or more) large numbers.If A > B, then GCF(A , B) = GCF(A - B, B) where A - B is smaller than A.Repeat, each time subtracting the smaller number from the bigger.Keep going until both numbers in the parentheses are the same: that number is the GCF of A and B.GCF by subtraction rather than factorising or division. Unfortunately, it can be quite slow. You could speed it up by doing A - 2B or A - 3B etc rather than A - B.True, and this property is useful for finding the greatest common factor (GCF) of two (or more) large numbers.If A > B, then GCF(A , B) = GCF(A - B, B) where A - B is smaller than A.Repeat, each time subtracting the smaller number from the bigger.Keep going until both numbers in the parentheses are the same: that number is the GCF of A and B.GCF by subtraction rather than factorising or division. Unfortunately, it can be quite slow. You could speed it up by doing A - 2B or A - 3B etc rather than A - B.True, and this property is useful for finding the greatest common factor (GCF) of two (or more) large numbers.If A > B, then GCF(A , B) = GCF(A - B, B) where A - B is smaller than A.Repeat, each time subtracting the smaller number from the bigger.Keep going until both numbers in the parentheses are the same: that number is the GCF of A and B.GCF by subtraction rather than factorising or division. Unfortunately, it can be quite slow. You could speed it up by doing A - 2B or A - 3B etc rather than A - B.True, and this property is useful for finding the greatest common factor (GCF) of two (or more) large numbers.If A > B, then GCF(A , B) = GCF(A - B, B) where A - B is smaller than A.Repeat, each time subtracting the smaller number from the bigger.Keep going until both numbers in the parentheses are the same: that number is the GCF of A and B.GCF by subtraction rather than factorising or division. Unfortunately, it can be quite slow. You could speed it up by doing A - 2B or A - 3B etc rather than A - B.
Yes.