The y-intercept (or y-intercepts) of an equation is where x = 0. Replace x with zero in the equation, and solve for y.
The answer depends on what information you are given - and in what form. If the equation of the curve is given in polar coordinates or in parametric form, the process is quite different to that required when given the Cartesian equation.
The y intercept will be the ordinate(y value) in the given co-ordinate.
y = mx + b, where m is the slope and b is the y-intercept.
Y=mc+b
A straight line in slope-intercept format has the equation: y = mx + b Where m is the slope, b the y-intercept. So, all you have to do is copy this equation, then replace "m" by the given slope, and "b" by the given y-intercept.
Slope = 0, intercept = 3
All that you know is that it goes through that one point. ^And if you have the equation of the line in slope-intercept form (y = mx + b) the "b" is the y-intercept. For example, if a y-intercept was at (0, -8), then the equation would be y = mx - 8, but you'd need more information to determine "m."
5
X + Y = 4. The standard form of a linear equation that makes the slope and Y-intercept obvious is: Y = (slope)X + (intercept). Re-arrange the given equation: Y = -X + 4 It's now in the standard form, and we can directly see that: Slope = -1 and Y-intercept = 4
The y intercept will be the ordinate(y value) in the given co-ordinate.
Depending on the type of story given, you need to determine the value of y where x is 0 on the graph or by substitution of the equation.
y = {slope}x + {y intercept}
y = mx + b, where m is the slope and b is the y-intercept.
Y=mc+b
A straight line in slope-intercept format has the equation: y = mx + b Where m is the slope, b the y-intercept. So, all you have to do is copy this equation, then replace "m" by the given slope, and "b" by the given y-intercept.
The y intercept is when x =0, so the answer is -6
-8
The y-intercept can be obtained from the straight line formula, y=mx+c. The y-intercept, c, is therefore given by c=-mx+y where m is the coefficient of gradient.