How do I find angle GET httpsgyazo.coma3d72c1b56c42b38e4a83ddadb760729?

Answer 1

The URL doesn't work, not even if I replace "https" by "https://".Update: I hadn't noticed that I had to add a slash after ".com". However, I don't know how to solve this. I guess I forgot the relevant theorems about circle sectors, etc.

Answer 2

The theorem that is used extensively here is that the angle subtended by an arc of a circle at the centre is double that subtended at the circumference within the other arc.

I cannot read the label of the point where EG meets the circle again and I am going to call it I.

Then

IVN = 74 => IGN = 37

NVA = 112 => NGA = 56

AVT = 32 => AGT = 16

Then

IGT = IGN + NGA + AGT = 109

=> EGT = 180 - IGT = 71 (angles on a straight line).

Now IVG (Reflex) = IVN + NVA + AVT + TVG = 74 +112 + 32 + 18 = 236

so IVG (Minor) = 360 - 236 = 124 => ITG = 62

IVN = 74 => ITN = 37

Then GTN = GTI + ITN = ITG + ITN = 62 + 37 = 99

=> ETG = 180 - GTN = 81 (angles on a straight line).

Finally, in triangle GET, GET = 180 - (EGT + ETG) = 180 -(71 + 81) = 28