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The answer will depend on the skewness of the distribution.

The Poisson distribution is defined for non-negative integers: 0, 1, 2, 3, 4 etc. So the lowest value is 0.

For a Poisson distribution with parameter l=1 (when it is very skew), the probability of the lowest two values, 0 and 1, is 0.368 each and the probability tails off rapidly for higher values.

The answer will depend on the skewness of the distribution.

The Poisson distribution is defined for non-negative integers: 0, 1, 2, 3, 4 etc. So the lowest value is 0.

For a Poisson distribution with parameter l=1 (when it is very skew), the probability of the lowest two values, 0 and 1, is 0.368 each and the probability tails off rapidly for higher values.

The answer will depend on the skewness of the distribution.

The Poisson distribution is defined for non-negative integers: 0, 1, 2, 3, 4 etc. So the lowest value is 0.

For a Poisson distribution with parameter l=1 (when it is very skew), the probability of the lowest two values, 0 and 1, is 0.368 each and the probability tails off rapidly for higher values.

The answer will depend on the skewness of the distribution.

The Poisson distribution is defined for non-negative integers: 0, 1, 2, 3, 4 etc. So the lowest value is 0.

For a Poisson distribution with parameter l=1 (when it is very skew), the probability of the lowest two values, 0 and 1, is 0.368 each and the probability tails off rapidly for higher values.

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10y ago

The answer will depend on the skewness of the distribution.

The Poisson distribution is defined for non-negative integers: 0, 1, 2, 3, 4 etc. So the lowest value is 0.

For a Poisson distribution with parameter l=1 (when it is very skew), the probability of the lowest two values, 0 and 1, is 0.368 each and the probability tails off rapidly for higher values.

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Q: How do the highest and lowest possible values for the variable compare in their probability of occurring to the values in the middle of the distribution?
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