(z + 1)(y + x)
2z + 5 - xz
mid point of xy
There appear to be 10 terms in the determinant. A determinant can only have a perfect number of terms. So something has gone wrong with the question. 1: x2 plus 1 2: xy 3: xz 4: xy 5: y2 plus 1 6: yz 7: 1 plus x2 plus y2 plus z2 8: xz 9: yz 10: z2 plus 1
between X and Y
xz + x + yz + y = (x + y)(z + 1)
(z + 1)(y + x)
2z + 5 - xz
mid point of xy
(z - 4)(x + y)
There appear to be 10 terms in the determinant. A determinant can only have a perfect number of terms. So something has gone wrong with the question. 1: x2 plus 1 2: xy 3: xz 4: xy 5: y2 plus 1 6: yz 7: 1 plus x2 plus y2 plus z2 8: xz 9: yz 10: z2 plus 1
It cannot be a property since it is not generally true!
between X and Y
It is 6+xz. The expression cannot be evaluated, factorised nor simplified. Since it is neither an equation nor an inequality, it cannot be solved. So the point of this question completely escapes me!
tata necton XZ plus petrol or Celts htk+petrol engine what school are you going to
XZ
Z is halfway between X and Y.